Answer:
19. 11
21. 119
Step-by-step explanation:
19.
(-5)² - [4(-3 ∙ 2 + 4)² + 3] + 5 =
= (-5)² - [4(-6 + 4)² + 3] + 5
= (-5)² - [4(-2)² + 3] + 5
= (-5)² - [4(4) + 3] + 5
= (-5)² - [16 + 3] + 5
= 25 - 19 + 5
= 6 + 5
= 11
21.
5 - 8[6 - (3 ∙ 2 - 8 + 2|4 ÷ -2 + (-3)| - 4) - 7 · 2] - 3² · (-2) =
= 5 - 8[6 - (3 ∙ 2 - 8 + 2|-2 + (-3)| - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (3 ∙ 2 - 8 + 2|-5| - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (3 ∙ 2 - 8 + 2(5) - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (6 - 8 + 10 - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (-2 + 10 - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (8 - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - 4 - 7 · 2] - 3² · (-2)
= 5 - 8[6 - 4 - 14] - 3² · (-2)
= 5 - 8[2 - 14] - 3² · (-2)
= 5 - 8[-12] - 3² · (-2)
= 5 - (-96) - 9 · (-2)
= 5 + 96 + 18
= 101 + 18
= 119
Answer: 1/67600
Step-by-step explanation:
probability that the code is 43MZ:
Probability = (Total Required outcome / total possible outcomes)
Possible outcomes (digit) = (00,.............. ..., 99)
2.) possible outcomes (alphabet) = (A, B,............... .., Z)
P(43MZ) = P(43) × P(M) × P(Z)
P(43) = 1/100
P(M) = 1/26
P(Z) = 1/26
THEREFORE ;
P(43MZ) = (1/100) × (1/26) × (1/26) = 1/67600
<h3>
The probability of winning the lottery is 
</h3>
Step-by-step explanation:
Here, the total numbers in the jackpot = 1 to 34
Now, the number that needed to be drawn = 5
The number of ways , 5 number can be drawn from total 34 numbers :

Also, in separate draw, the correct number drawn = 1
So, the number of ways that can be done = 30 C 5 x 37
= 278,256 x 37 = 10,295,472
Now, P(win) = 
Hence, the probability of winning the lottery is 
<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>B</em><em>.</em><em>.</em>
10.7703 to the nearest tenth is 10.8