Answer: width = 60 yd
and Length= 110 yd
Step-by-step explanation:
Step 1
Perimeter of rectangle field is given as 2 ( L+ b)
Let the width be represented as x
'and length which is 50 yd longer than the width be
=x+ 50
such that the Perimeter with 340 yd can be expressed as
Perimeter = 2 ( L+ b) = 2L + 2B
Step 2---Solving
Perimeter = 2L + 2B
340 = 2(X+ 50) + (2 x)
340 = 2X+ 100 + 2X
340=4X + 100
340-100=4X
240= 4X
X= 240/4
X= 60
Width = x = 60 yards
;Length = 50 + x= 50 + 60 = 110yards
the easiest way to find the answer is to multiply 2 x 2 and then add two zeros on the end. the answer is 400
Answer:
Sorry pal
Step-by-step explanation:
1) x^2=36
x=6
3) x^2-8x+13=0 —> x= (8±√64-4(1)(13))/2(1)
x=4±√3
5) x^2-6x+9-k=0 —> x=(6±√36-4(1)(9-k))/2(1) —> (6±√4k)/2 —> (6±2√k)/2
x=3±√k
7) y=x^2-4x+11 —> y-11=x^2-4x —> take the half of the coefficient of the single x term and square it and add it on both sides —> y-11+4=x^2-4x+4 —> y-7=(x-2)^2 —> y=(x-2)^2+7
Minimum: (2,7)
Maximum: n/a
X intercepts: none (never crosses the x-intercept)
9) y=x^2+2x-8 —> y+8+1=x^2+2x+1 —> y=(x+1)^2-9
Minimum: (-1,-9)
Maximum: n/a
x-intercepts: (x+4)(x-2) —> (-4,0),(2,0)
11) c
13) (x+7)(x+3)
15) x=(-6±√36-4(1)(10))/2 —> x=(-6±√-4)/2 —> (-6±2i)/2
x=-3±i OR no real solutions
X is amount of plates 10lbs and f(x) is the function