Answer:
2.807
Step-by-step explanation:
In order to make comparisons between two numbers we use ratios.
Ratios can be written as fraction, with a colon or with the word to.
The ratio 52,853:18,827 or
52,853/18,827 = 2.807
Answer:
flip the inequality sign when multiplying or dividing on a negative number
Step-by-step explanation:
Hope this helped :]
Answer
300
Step-by-step explanation:
multiply by each other
Answer:
3rd
Step-by-step explanation:
I think thats how u fill it
Answer:
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.
This is 1 subtracted by the pvalue of Z when X = 85. Then



has a pvalue of 0.7486.
1 - 0.7486 = 0.2514
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.