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Artyom0805 [142]
3 years ago
14

3.

Mathematics
1 answer:
krek1111 [17]3 years ago
6 0

Answer:

2

Step-by-step explanation:

Let L be a real number.

\lim_{x \rightarrow 2}f(x) equals L if:

\lim_{x \rightarrow 2^-}f(x)=L

\lim_{x \rightarrow 2^+}f(x)=L

----------------------------

\lim_{x \rightarrow 2^-}f(x) means what does y get close to as we move x closer to 2 from the left. Please look at the orange to see what that looks like visually.

We see that y tends to 2.

This means:

\lim_{x \rightarrow 2^-}f(x)=2

-----------------------------

\lim_{x \rightarrow 2^+}f(x) means what does y get close to as we move x closer to 2 from the right. Please look at the blue to see what that looks like visually.

We see that y tends to 2.

This means:

\lim_{x \rightarrow 2^+}f(x)=2

----------------------------

Therefore,

\lim_{x \rightarrow 2}f(x)=2.

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#22 im not sure what the first step is
swat32
To rotate a point 180° about the origin, you simply have to multiply -1 to the first and second coordinate. For your problem, just do that for all the points and list them out.
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3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

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The lines graphed below are parallel. The slope of the red line is -4/3. What is the slope of the green line?
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-4/3

Parallel lines have the same slope.
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