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dsp73
2 years ago
6

Help Meh Once Again :) (5 + 7)^2 =

Mathematics
2 answers:
Nastasia [14]2 years ago
7 0

Answer:

144

Step-by-step explanation:

Think of PEMDAS(Please(Parenthesis),Excuse(Exponents),My Dear(Multiplication and Division), Aunt Sally(addition and subtraction).

Since this has Parenthesis you would have find out what was in the Parenthesis  first(Please).

5+7=12

Now you look for exponents. The exponent is 2 and that means multiply the 12 by itself (12(12).

Giving you 144.

Lubov Fominskaja [6]2 years ago
3 0

Answer:

144

Step-by-step explanation:

PEMDAS

(12)^2

144

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Urgent!
AfilCa [17]

Answer:

The polynomial will be P(x) = - 5 (x + 2)²(x - 3)

Step-by-step explanation:

The degree of the polynomial P(x) is 3 and it has zeros at x = - 2 with multiplicity 2 and at x = 3 with multiplicity 1.

Therefore, (x + 2)² and (x - 3) are the factors of the equation.

Let the polynomial is

P(x) = a(x + 2)²(x - 3) ........... (1)

Now, the polynomial passes through the point (2,80).

So, from equation (1) we gat,

80 = a(4)²(-1)

⇒ a = - 5

Therefore, the polynomial will be P(x) = - 5 (x + 2)²(x - 3) (Answer)

6 0
2 years ago
Determine the direction that is parabola opens: y = -5x^2 -10x -13
Lunna [17]
The parabola opens down, since the 'a' value of the equation is a negative value.
8 0
3 years ago
What does a obtuse angle look like .
Soloha48 [4]

Answer:

An obtuse angle is more than 90°. We know that a 90° angle, also known as a right angle, is in the shape of an "L".

So, an obtuse angle looks wider than an "L".

<em>Hope this helps! I would really appreciate it if you would please mark me brainliest! Have a blessed day!</em>

8 0
3 years ago
6) What is the mean (average) of this set of data: 3 4 6 7 10 15 19 21
Natali5045456 [20]

Answer:

10.62

Step-by-step explanation:

Mean can be described as the average of a sum of numbers, it can be calculated by sum ing all the numbers together and then diving by the total

The mean of the set of numbers shown in the question above can be calculated as follows

3+4+6+7+10+15+19+21/8

= 85/8

= 10.62

Hence the mean is 10.62

6 0
3 years ago
The tangent to the circle x^2+y^2=18 is parallel to the tangent x+y=6
liubo4ka [24]

Answer:

y = -x - 6

Step-by-step explanation:

If we are looking for the equation of the line tangent to the circle, we have to find the first derivative of the circle function.  If that tangent line is to be parallel to the given tangent line, we need to find the slope of the the given tangent line and make sure the slope of the line we are looking for is the same.  First let's find the slope of the given tangent.  If the given tangent is x+y=6, then to find the slope, solve for y:

y = -x + 6.  So the slope of that line, and also the slope of the tangent we are solving for, is -1.  Hold that thought while we find the derivative of the function.  Using implicit differentiation, we find the derivative to be:

2x+2y\frac{dy}{dx}=0

Solving for the slope (dy/dx) gives us:

2y\frac{dy}{dx}=-2x and

\frac{dy}{dx}=\frac{-2x}{2y} so

\frac{dy}{dx}=-\frac{x}{y}

Subbing in the value of the slope we found:

-1=-\frac{x}{y} so

-y = -x or, equivalently,

y = x.  Now that we know that y and x are the same value, we can go back to the original circle to find out what they both are by substitution.  If y = x, we make the substution:

If x^2+y^2=18, then

y^2+y^2=18 and

2y^2=18 and

y^2=9 so

y = ±3

We will choose the negative root (you'll see why in a second) and sub that in for both y and x since y and x are th same number.  Going back to the fact that the slope is -1:

y - (-3) = -1(x - (-3)) simplifies a bit to:

y + 3 = -x - 3 which gives us, in slope-intercept form:

y = -x - 6

That is the equation of the tangent to the circle that is parallel to the given tangent.

If we would have chosen the principle (or positive) root of 3, our equation would have looked like this:

y - 3 = -1(x - 3) and

y = -x + 3 + 3 so

y = -x + 6.  Notice that that is the EXACT SAME EQUATION as the given tangent.  That's why we have to pick the negative 3 as our root.

Good luck in your calculus class!  Make sure you post your questions in here!  Many of us LOVE the challenge of calculus!

3 0
3 years ago
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