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3 years ago

12

Help if can 8 pts

2 answers:

maw [93]3 years ago

8 0

45 because 36 times 125% is 45

mezya [45]3 years ago

8 0

The answer is 45. hope this helps

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How do I solve this problem, or can I have an answer to this problem?

azamat

Well first you have to know what i is. i is the sqrt of -1 so try doing 3+5(sqrt-1)/1+sqrt-1. I don't know how to solve it though sorry

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3 years ago

Devon made a box with length x+1, width x+3, and height x-3. What is the volume of Devon's box as a function of x?

erica [24]

Answer:

(a)

$V=x^3+x^2-9x-9$

(b)

$x=10$

(c)

$x=\frac{7}{2}$

Step-by-step explanation:

we are given

length is x+1

$L=x+1$

width is x+3

$W=x+3$

height is x-3

$H=x-3$

(a)

we can use volume formula

$V=L\times W\times H$

now, we can plug it

$V=(x+1)\times (x+3)\times (x-3)$

now, we can simplify it

$V=x^3+x^2-9x-9$

(b)

we are given volume =1001

so, we can set V=1001

and then we can solve for x

$V=x^3+x^2-9x-9=1001$

now, we can factor it

$\left(x-10\right)\left(x^2+11x+101\right)=0$

$x-10=0$

$x=10$

(b)

we are given volume

so, we can set

$V=14\frac{5}{8}=\frac{14\times 8+5}{8}$

$V=\frac{117}{8}$

and then we can solve for x

$V=x^3+x^2-9x-9=\frac{117}{8}$

now, we can factor it

$8x^3+8x^2-72x-189=0$

$\left(2x-7\right)\left(4x^2+18x+27\right)=0$

$2x-7=0$

$x=\frac{7}{2}$

8 0

3 years ago

Describe a real world situation between the area of a rectangle and its width, as the width varies and the length stays the same

raketka [301]

Area of rectangle = length x width If length is constant, say c and width is variable, say x Area of rectangle = y = cx This means Area will vary linearly with width and will represent a line with slope... hope I helped

4 0

3 years ago

What do you call it when police interrogate a cows husband

aniked [119]

The answer is
"Question-a-bull"

5 0

3 years ago

3 1/2 - 1 1/3 x x= 1

slamgirl [31]

Answer:

The value of x for the given expression is $\frac{15}{8}$

Step-by-step explanation:

Given as :

<u>The expression is written </u>

3 $\dfrac{1}{2}$ - 1 $\dfrac{1}{3}$ × x = 1

Or, 1 $\dfrac{1}{3}$ × x = 3 $\dfrac{1}{2}$ - 1

Or, $\frac{(1\times 3) + 1}{3}$ × x = $\frac{(3\times 2) + 1}{2}$ - 1

Or, $\dfrac{4}{3}$ × x = $\dfrac{7}{2}$ - 1

Or, $\dfrac{4}{3}$ × x = $\dfrac{7-2}{2}$

Or, $\dfrac{4}{3}$ × x = $\dfrac{5}{2}$

∴ x = $\frac{\frac{5}{2}}{\frac{4}{3}}$

Or, x = $\frac{5\times 3}{2\times 4}$

I.e x = $\frac{15}{8}$

So, The value of x = $\frac{15}{8}$

Hence The value of x for the given expression is $\frac{15}{8}$ Answer

6 0

3 years ago