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topjm [15]
3 years ago
14

At the beginning of the year, Mr. and Mrs. Smith's portfolio is made up of $200 cash, stocks, with value of $236,000, and bonds

worth $163,000. Mr. Smith received $5,000 in dividends and bond interest of $4,150. At year end, Mr. Smith has $200 cash, stocks $250,000 and bonds worth $159,000. What was Mr. Smith's total return for the year?
Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

4.797% of total return

Step-by-step explanation:

In this case, first, let's gather the data:

Beggining of the year:

200 + 236,000 + 163,000 = 399,200$

End of the year:

200 + 250,000 + 159,000 = 409,200$

This means that between the beggining and the end of the year, Mr Smith only had a gain of 10,000$.

To get the final return, we need to add this gain to the dividens and interest which is:

10,000 + 5,000 + 4,150 = 19,150$

So, the total return would be the percentage between this gaining and the innitial amount:

% = 19,150 / 399,200 * 100

% = 4.797%

And this is the total return.

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689x+47x-89 dose anyone know how to solve this?
Korvikt [17]

Answer:

736x-89

Step-by-step explanation:

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What is<br> 7.5% tax on<br> a $18<br> sweater?<br><br> 19.35 or 1.35
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Step-by-step explanation:

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3 years ago
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Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a?
BlackZzzverrR [31]

Answer:

\boxed{\sf a = 9 }

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

\sf\longrightarrow 3x - 2y +7=0

\sf\longrightarrow 6x +ay -18 = 0

Step 1 : <u>Conver</u><u>t</u><u> </u><u>the </u><u>equations</u><u> in</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u><u>of</u><u> the</u><u> line</u><u> </u><u>.</u>

\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}

and ,

\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}

Step 2: <u>Find </u><u>the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> </u><u>lines </u><u>:</u><u>-</u>

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

\sf\longrightarrow Slope_1 = \dfrac{3}{2}

And the slope of the second line is ,

\sf\longrightarrow Slope_2 =\dfrac{-6}{a}

Step 3: <u>Multiply</u><u> </u><u>the </u><u>slopes </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow \dfrac{3}{2}\times \dfrac{-6}{a}= -1

Multiply ,

\sf\longrightarrow \dfrac{-9}{a}= -1

Multiply both sides by a ,

\sf\longrightarrow (-1)a = -9

Divide both sides by -1 ,

\sf\longrightarrow \boxed{\blue{\sf a = 9 }}

<u>Hence </u><u>the</u><u> </u><u>value</u><u> of</u><u> a</u><u> </u><u>is </u><u>9</u><u> </u><u>.</u>

8 0
3 years ago
(7x+14) (15x-4) solve for x (20 points
Misha Larkins [42]

Answer:

The value of x .

7x-14= 15x

-14 =8x

x= -7/4

Step-by-step explanation:

sorry if im wrong

7 0
3 years ago
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