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3 years ago

How many thousands are there in 800,000

2 answers:

5 0

To find the solution to the problem, we can divide the number by 1,000.
Because we're trying to find how many 1,000's are there in this 800,000.

800,000 / 1,000 = 800

There are 800 1,000's in that number.

maxonik [38]3 years ago

5 0

Read the number out loud. You'll say "eight hundred thousand". There are 800 thousands in it.

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Tell whether the triangles are similar.

Vilka [71]

Answer: I think it’s not similar becaus of the size.

It’s also a different number so it’s a no.

Step-by-step explanation:

4 0

3 years ago

M(x)=x^2-3x N(x)=x-5 MN(-1)= ? A.18 B.-20 C.-22 D. -24

schepotkina [342]

Answer:

d. -24

Step-by-step explanation:

M(-1)=(-1)^2-3(-1)

M(-1)=1+3

M(-1)=4

N(-1)=-1-5

N(-1)=-6

MN(-1)=(4)(-6)

MN(-1)=-24

3 0

3 years ago

A rectangle is constructed with its base on the x-axis and two of its vertices on the parabola yequals=4949minus−xsquared2. Wha

xxMikexx [17]

Answer:

Dimensions of rectangle : Width = $2x$ , Length = $49 - x^2$

Area of Rectangle = $98x - 2x^3$

Step-by-step explanation:

A rectangle constructed with its base on the x-axis and two of its vertices on the parabola

Supposing coordinates of upper right vertex of rectangle are P = $(x,y)$

Due to parabola symmetry, width of rectangle is twice the horizontal (X) axis distance between Y axis & point P.

Width of rectangle : $2x$

Length of rectangle : $y = 49 - x^2$

Area of Rectangle = Length x Width

( $2x$ ) ( $49 - x^2$ )

= $98x - 2x^3$

8 0

3 years ago

Find he prodct 4(-2)

Simora [160]

Answer:

-8

Step-by-step explanation:

four times two equals eight, positive times negative equals negative, so -8

6 0

2 years ago

Read 2 more answers

There are x number of students at helms. If the number of students increases by 7.8% each year, how many students will be there

vodomira [7]

There will be 1.078x students next year and equation is number of students in next year = x + 7.8% of x

<h3>Solution:</h3>

Given, There are "x" number of students at helms.

The number of students increases by 7.8% each year which means if there "x" number of students in present year, then the number of students in next year will be x + 7.8% of x

Number of students in next year = number of students in present year + increased number of students.

$\begin{array}{l}{\text { Number of students in next year }=x+7.8 \% \text { of } x} \\\\ {\text { Number of students in next year }=x\left(1+\frac{7.8}{100}\right)} \\\\ {\text { Number of students in next year }=x(1+0.078)=1.078 x}\end{array}$

Thus there will be 1.078x students in next year

3 0

3 years ago