Question

Compute the permutations and combinations. a farmer buys 2 cows, 3 pigs, and 10 sheep from a seller who has 7 cows, 4 pigs, and 10 sheep. how many choices of animals does he have?

Answer 1

Answer:

Total number of ways = 84

Step-by-step explanation:

Number of choices farmer has for cows = 2 out of 7

Number of choices farmer has for pigs = 3 out of 4

Number of choices farmer has for cows = 10 out of 10

$\text{Number of ways of choosing cows = }_2^7\txterm{C}=21$

$\text{Number of ways of choosing cows = }_3^4\txterm{C}=4$

$\text{Number of ways of choosing cows = }_{10}^{10}\txterm{C}=1$

All these three groups of different animals can make different groups when taken together

Thus, Total number of ways = 21 × 4 × 1

⇒  Total number of ways = 84

Answer 2

The farmer has 26 choices