Let the total amount that Sarah deposited be $x
using the annuity formula:
A=P[((1+r)^n-1)/r]
A=future value
r=rate
n=number of years
from the information given:
A=$500000
r=2.75%
n=65-42=23 years
p=$x
thus plugging our values in the formula we get:
500000=x[((1+0.0275)^(23)-1)/(0.0275)]
500000=31.50x
x=15,872.04883
She deposited 15,873.04883 per year
The monthly deposit will therefore be:
15873.04883/12=$1322.67
Answer:
7,173
x = 7
Step-by-step explanation:
Within the question it gives two examples.
x = 0 corresponds to 2000
x = 1 corresponds to 2001
If you pay close attention the x-value is always the same as the last digits in the year. So with 2007 the last digit is 7, which then leads us to determine that
x = 7
f (x) = -327 (7) + 9462
f (x) = -2289 + 9462 = 7173
Answer:
11/3
<em>Alternative Form: </em>3 2/3, 3.6
Step-by-step explanation:
44/12
Dive the numerator and denominator by 4
44/4 / 12/4
11/ 12/4
11/3
Answer:
the exact length of the midsegment of trapezoid JKLM = 
i.e 6.708 units on the graph
Step-by-step explanation:
From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.
Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:
Thus; the exact length of the midsegment of trapezoid JKLM = i.e 6.708 units on the graph
