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OLEGan [10]
3 years ago
15

The area of the figure

Mathematics
1 answer:
Anastasy [175]3 years ago
5 0
The answer is 28.86 cm^2

You have to subtract the area of the missing triangular piece (4cm) and the quarter of a circle (~3.14cm) from the square (36cm).

Hope this helps!!
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Tanya is 42 years old. she would like to open aretirement account so she will have half a million dollars in the account when sh
gladu [14]
Let the total amount that Sarah deposited be $x
using the annuity formula:
A=P[((1+r)^n-1)/r]
A=future value
r=rate
n=number of years
from the information given:
A=$500000
r=2.75%
n=65-42=23 years
p=$x
thus plugging our values in the formula we get:
500000=x[((1+0.0275)^(23)-1)/(0.0275)]
500000=31.50x
x=15,872.04883
She deposited 15,873.04883 per year
The monthly deposit will therefore be:
15873.04883/12=$1322.67
7 0
3 years ago
shuan polleted a point on the number line by drawing 5 equally marks 0 and 1 and placing a point on the third mark he clams that
Dimas [21]
<h2><em>add my discord Big_Man #8293</em></h2>
6 0
2 years ago
Read 2 more answers
Help me please!!!! The question is in the picture^^^
Aleksandr [31]

Answer:

7,173

x = 7

Step-by-step explanation:

Within the question it gives two examples.

x = 0 corresponds to 2000

x = 1 corresponds to 2001

If you pay close attention the x-value is always the same as the last digits in the year. So with 2007 the last digit is 7, which then leads us to determine that

x = 7

f (x) = -327 (7) + 9462

f (x) = -2289 + 9462 = 7173

6 0
3 years ago
What is the ratio 44/12 in simplest form
mylen [45]

Answer:

11/3

<em>Alternative Form: </em>3 2/3, 3.6

Step-by-step explanation:

44/12

Dive the numerator and denominator by 4

44/4 / 12/4

11/ 12/4

11/3

3 0
3 years ago
Read 2 more answers
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
2 years ago
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