i put it in coments sence it says it is inapropreait
Answer:
x = 8, y = 
Step-by-step explanation:
Both 8 and x sides are congruent so they're equal.
Add 64 + 64.
Square root 128
Final answers: x = 8, y =
Answer:
No real roots
Step-by-step explanation:
Given
7x² + 5x + 1 = 0 ← in standard form
with a = 7, b = 5, c = 1
To determine the nature of the roots use the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then the roots are not real
Here
b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3
Thus the 2 roots are not real
Factor ouf 3x
3x(12x^2-5x-2)
factor
(3x)(3x-2)(4x+1)
