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kozerog [31]
2 years ago
9

Write a relationship for a function whose k(x) values are 5 more than four times the principal square root of x .

Mathematics
1 answer:
bearhunter [10]2 years ago
4 0

Answer:

k(x)=5+4\sqrt{x}

Step-by-step explanation:

Write a function whose k(x) values are 5 more than four times the principal square root of x.

So,

the principal square root of x =\sqrt{x};

four times the principal square root of x =4\sqrt{x};

5 more than four times the principal square root of x =5+4\sqrt{x};

Thus,

k(x)=5+4\sqrt{x}

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Answer:

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Step-by-step explanation:

Given:

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1.

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8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

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