Answer:
Not possible.
Step-by-step explanation:
Addition of Matrix A and Matrix B is possible only if the order of matrix A is same as the order of matrix B.
Order of a matrix with 
rows and 
columns is 
.
Here, matrix A is ![\left[\begin{array}{ccc}2&-4\\-4&10\\0&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-4%5C%5C-4%2610%5C%5C0%26-8%5Cend%7Barray%7D%5Cright%5D)
Matrix B is ![\left[\begin{array}{ccc}0&-4&6\\2&-10&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-4%266%5C%5C2%26-10%264%5Cend%7Barray%7D%5Cright%5D)
.
Multiplying a matrix by a constant doesn't change its order.
So, order of matrix A is 
as it has 3 rows and 2 columns.
The order of matrix 3B is 
as it has 2 rows and 3 columns.
Therefore, addition is not possible as the order is different.
Answer:
um the answer is D
Step-by-step explanation:
we are given
investment amount is 2300
so,
it is compounded monthly
so,
n=12
now, we can use formula
now, we can plug values
t=7/12
and we get
now, we can find FV
............Answer
Answer:
3,125 i think sorry if this is incorrect....
Step-by-step explanation:
Answer:
P = $ 3,125.00
Equation:
P = I / rt
Calculation:
First, converting R percent to r a decimal
r = R/100 = 8%/100 = 0.08 per year,
then, solving our equation
P = 500 / ( 0.08 × 2 ) = 3125
P = $ 3,125.00
The principal required to
accumulate interest of $ 500.00
on a rate of 8% per year for 2 years is $ 3,125.00.
No. there are no integers between 0 and 1 because integers are the numbers which don't have any fractions and decimals. between 0 and 1 only decimals and fractions are present
