If he attempted 45 passes, find how many passes he completed. Round to the nearest whole number of necessary.
Hello.
In your question, we can see that the points Q, P, and R can be assumed that they are in a straight line, meaning that the angle measures will add up to 180 (think of half a circle, which is 360 degrees).
This means that every angle added up will add up to 180 degrees.
Meaning we can set up the below equation:
After finding , we can plug it back in to each expression for each angle measure.
∠QPS =
∠SPT =
∠TPR =
Hope this helps!
You would do
3(1p) =3p-n+4
and then add a 1 to the n
3p-1n+4
add 1n+4
3p-5n
hope this helps! tysm
Consider one pyramid
Side length of base = 1.5cm and its height is 1 cm
Slant height of one of the lateral faces = sqrt(1^2 + 0.75^2) = 1.25 cm
Area of one of the triangular faces = 0.5 * 1.5* 1.25 = 0.9375 cm^2
There are 8 of these so the required surface area = 8 * 0.9375
= 7.5 cm^2 Answer
Answer:
t=6
Step-by-step explanation: