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3 years ago

Write an equation that represents this comparison sentence. 24 is 4 times as many as 6

Mathematics

2 answers:

Butoxors [25]3 years ago

7 0

Answer:6 x 4 = 24

Step-by-step explanation:

im not sure what was so hard

dmitriy555 [2]3 years ago

6 0

Answer:

4x6=24 its just you multiply the two smallest numbers

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AT this day camp, the greatest number of campers each group can have is 14 campers.

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3 years ago

Find the area of segment CED given the following information:

Hitman42 [59]

Area of sector CAD = 72 / 360 x pi x 6^2 = 7.2pi = 22.6195 in^2

Therefore, area of segment CED = 22.6195 - 17.18 = 5.44 in^2

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3 years ago

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5 liters of water weighs 11 pounds. A bucket contains 143 pounds of water. How many liters of water are in the bucket

slavikrds [6]

Answer:

65 liters

Step-by-step explanation:

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3 years ago

Line L1, L2 and L3 are in the same plane, L1 is perpendicular to L2, and L3 is parallel to L1. which of the following statement

exis [7]

Only Statement 2 is surely correct.
because there maybe chances that the line L1 and L3 lies above the line L2 and they can also fulfill the condition of perpendicularity so we can't be sure about statement 3 & statement 1 is clearly incorrect

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3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

3 years ago