Help me with this please so I can finish this class and move on to the others
2 answers:
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Answer:
g(x) = -Ix - 4I + 1
Step-by-step explanation:
* Lets revise some transformation
- If the function f(x) translated horizontally to the right by h units, then
the new function g(x) = f(x - h)
- If the function f(x) translated horizontally to the left by h units, then
the new function g(x) = f(x + h)
- If the function f(x) translated vertically up by k units, then the new
function g(x) = f(x) + k
- If the function f(x) translated vertically down by k units, then the
new function g(x) = f(x) – k
- A vertical stretching is the stretching of the graph away from the
x-axis
- If k > 1, the graph of y = k • f(x) is the graph of f(x) vertically
stretched by multiplying each of its y-coordinates by k.
- A vertical compression is the squeezing of the graph toward
the x-axis.
- If 0 < k < 1 (a fraction), the graph of y = k • f(x) is the graph of f(x)
vertically compressed by multiplying each of its y-coordinates by k.
- If k should be negative, the vertical stretch or compress is followed
by a reflection across the x-axis.
* Lets solve the problem
∵ The graph of f(x) represented by the function f(x) = -2Ix - 4I + 2
∵ The y-intercept of f(x) is -6 and y-intercept of g(x) is -3
∵ -3/-6 = 1/2
∴ We will multiply f(x) by 1/2 to get the y-intercept of g(x)
- That means f(x) is compressed vertically by scale factor 1/2 to be g(x)
∴ g(x) = 1/2 [ -2Ix - 4I + 2]
∴ g(x) = -Ix - 4I + 1
- To be sure from the answer check the point (4 , 2) in f(x), when
we multiply the y-coordinate by 1/2 the point change to (4 , 1)
which is belong to g(x) that means f(x) translate 1 unit down to be
g(x)
∴ g(x) = -Ix - 4I + 1
The graph of line 3x-y= -1 will be as follows.
What is a line?
A line is an endlessly long, straight object that, despite being drawn with a minimum width, is considered to have no particular width in mathematics.
Main Body:
slope = m = 3 point = (0,1)
The formula for one point form for a line is -
y-y₁ = m(x-x₁)
y- 1 = 3(x-0)
3x-y =-1
Now the graph for the line will be plotted by using the point given and the slope--
on Graph mark the point (0,1)
To learn more about line click on the link below
#SPJ1
