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3 years ago

9

Please help with question A and show work!! thank you

1 answer:

Digiron [165]3 years ago

8 0

The equation for the line of reflection is x = 2.
If you drew a vertical line crossing the x-axis on x = 2, the drawing will be the same on the left and right side, as if one side was drawn then exactly copied on the other side but flipped.
The figure is symmetrical, and x = 2 is the line of symmetry.
Hope this helps!

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Maria and victor each play a video game. The ratio of the number of points Maria scores to the number of points victor scores is

zvonat [6]

Answer:

Step-by-step explanation:

I don't know what a tape diagram is but I can give you the equation and the answer.

Let Victor have x points

Let Maria have y points

y = x + 424

y/x = 5/3 Cross multiply

3y = 5x Divide by 3

y = 5x/3 I Could have just multiplied by x

y = x + 424

5x/3 = x + 424 Multiply both sides by 3

5x = 3x + 1272 Subtract 3x from both sides.

5x-3x = 1272 Combine the left.

2x = 1272 Divide by 2

2x/2 = 1272/2

x = 636

Victor Scored 636 points

Maria Scored 636 + 424 = 1060

7 0

2 years ago

Can anyone help me with my homework

damaskus [11]

1. Two steps left and one step up to the computer lab
2. Music class
3. 9 left and 5 down
4. Science and math
5. 1,4
6. Second quadrant, where the entrance is

6 0

3 years ago

Answer this question step by step

KiRa [710]

I hope this help you

3 0

3 years ago

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

3 years ago

Suppose there are signs on the doors to two rooms. The sign on the first door reads "In this room there is a lady, and in the ot

9966 [12]

Answer:

The lady is on the second door

Step-by-step explanation:

we have that

The sign on the first door reads "In this room there is a lady, and in the other one there is a tiger"

The sign on the second door reads "In one of these rooms, there is a lady, and in one of them there is a tiger."

so

The sign on the second door is true

The sign on the first door is true or false

Since one of these signs is true and the other is false, the sign in the first door must be false

therefore

The lady is on the second door

5 0

3 years ago