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aivan3 [116]
3 years ago
10

The temperature fell from 0Degrees Fahrenheit to 6 and three-fifthsDegrees Fahrenheit below 0Degrees Fahrenheit in 2 and one-fif

th hours. What was the temperature change per hour?
Mathematics
2 answers:
masya89 [10]3 years ago
8 0

Answer:

-3 degrees per hour.

stepan [7]3 years ago
7 0

Answer:

B) -3                                 (Sorry if its overwhelming)

Explanation:

First, we have the given information of the weather over a <em>2</em> and <em>1/5</em> <em>span</em>

And we are asked to find the change per hour

We can first start by finding the <em>change</em> for 2 and 1/5 hours:

- Subtract the first amount by the second amount.

= (-6 3/5) - 0

= (-6 3/5) + 0

= -6 3/5

Now that we have the change for <em>2 and 1/5 hours</em> we must find the <em>change</em> per hour:

- Divide the given dividend by the given divisor

= -6 3/5 ÷ 2 1/5

= -3

Hence, the temperature <em>change per hour</em> over a 2 1/5 hour span is -3° per hour

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Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

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Given as , for regular hexagonal pyramid :

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Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

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So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

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