It would be 6(4a2 - 3)
you would factor out just the 6 because the 18 doesn’t a a term with it like 34a2 does. then just divide normally to get ur answer 6(4a2 - 3)
In order to solve for a, we must isolate it. To do this, we should add c to both sides, making a the only term on the left.
Final answer: a=c+d-r
<span>4 1/5-2 1/2 = 1.7
1.7 to fraction is 1 7/10
Answer: 1 7/10</span>

Factor square root of 32: 2^5/2.
Factor 4: 2^2

Cancel 2 1/2= 2 1/2.
2 1/2= square root of 2.
Answer: 
Hope this helps :)
Step-by-step answer:
Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals
Ra = 2Fcos(a) ..............................(1)
Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals
Rb = 2Fcos(b)..............................(2)
We are given that
Ra = 2Rb ....................................(3)
Substitute (1) & (2) in (3) gives
2Fcos(a) = 2(2Fcos(b))
Expand
2Fcos(a) = 4Fcos(b)
Simplify
cos(a) = 2 cos(b) QED
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