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bearhunter [10]
3 years ago
10

An open box is formed from a rectangular piece of cardboard whose length is 8cm more than its width by cutting squares of 2cm fr

om each corner and folding. If the volume = 256 what are the dimensionS?
Mathematics
1 answer:
Serggg [28]3 years ago
3 0
If the width of the cardboard = x cm then its length is given by x + 8 cm.
Then the length of the box will be x + 8 - 2(2) =  x + 4
and the width = x - 2(2) = x - 4 cm The height is 2 cm 

Volume = h*w*l = 2(x - 4)(x + 4) = 256
2(x^2 - 16) = 256
x^2 - 16 = 128
x^2  = 144 
x = 12 cm 

Dimensions of the box are:-

length =  12 + 4 =  16cm
width = 12 - 4 = 8 cm
height = 2 cm



















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To calculate function value f(k) for a function f(x), we substitute variable x = k, in the function f(x).

<h3>How to solve the question?</h3>

In the question, we are asked to find the function value for the function f(x) = 3x² + 2x - 6 for:

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