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RoseWind [281]
4 years ago
12

Hi guys can u pls help me with this problem thanx

Mathematics
1 answer:
salantis [7]4 years ago
8 0

Answer:

\frac{1}{4} left

Step-by-step explanation:

The question says she used \frac{1}{2} of it, so she probably used \frac{1}{2} of it. I'm assuming this is an error in the question, and it should be asking how much is left. To solve for that:

\frac{3}{4} - \frac{1}{2}

make denominators equal

(\frac{2}{2} × \frac{3}{4}) - (\frac{1}{2} × \frac{4}{4})

\frac{6}{8} - \frac{4}{8}

\frac{2}{8}

\frac{1}{4}

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HELP!!! Choose the best answer.
maxonik [38]

Answer:

x^3y^2+x^2y^3-x^2-y^2

Step-by-step explanation:

I will edit my answer if you need my explanation.

If this has helped you please mark as brainliest

4 0
3 years ago
Given that z is a standard normal random variable, find z for each situation. The area between 0 and z is .4750. Answer The area
algol13

Answer:

P(0

And solving for z we have

P(Z

And we can find the value for z with the following excel code:

"=NORM.INV(0.975,0,1)"

And we got z =1.96

P(Z>z)= 0.1314

And we can use the complement rule and we got:

P(Z>z) = 1-P(Z

P(Z

And we can find the value for z with the following excel code:

"=NORM.INV(0.8686,0,1)"

And we got z =1.120

P(Z

And we can find the value for z with the following excel code:

"=NORM.INV(0.67,0,1)"

And we got z =0.440

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

We want this probability:

P(0

And solving for z we have

P(Z

And we can find the value for z with the following excel code:

"=NORM.INV(0.975,0,1)"

And we got z =1.96

For the next part we want to calculate:

P(Z>z)= 0.1314

And we can use the complement rule and we got:

P(Z>z) = 1-P(Z

P(Z

And we can find the value for z with the following excel code:

"=NORM.INV(0.8686,0,1)"

And we got z =1.120

For the next part we want to calculate:

P(Z

And we can find the value for z with the following excel code:

"=NORM.INV(0.67,0,1)"

And we got z =0.440

6 0
3 years ago
A stadium has 48,000 seats. Seats sell for ​$25 in Section​ A, ​$20 in Section​ B, and ​$15 in Section C. The number of seats in
Ira Lisetskai [31]
I had a super-ugly equation that didn’t work, but it got me close. (24,000/12,000/12,000 or so)
Then I adjusted the numbers to make the money work.

I’m sorry I can’t help more.

24,000(25) + 14,200(20) + 9,800(15)
= 600,000 + 284,000 + 147,000 = 1,031,000

Section A = 24,000 seats
Section B = 14,200 seats
Section C = 9,800 seats

14,200 + 9,800 = 24,000 seats
5 0
3 years ago
Find the slope of the line that contains (−3,5) and (3,−9).
Ratling [72]

Answer:

-7/3

Step-by-step explanation:

You would use the slope formula which is (y_2-y_1)/(x_2-x_1).

8 0
3 years ago
Read 2 more answers
Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th
xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

P:(x - 1)^2 + (y + 6)^2 = 9

Q:(x + 4)^2 + (y + 14)^2 = 4

Solving (a): The distance between both

The equation of a circle is:

(x - h)^2 + (y - k)^2 = r^2

Where

Center: (h,k)

Radius:r

P and Q can be rewritten as:

P:(x - 1)^2 + (y + 6)^2 = 3^2

Q:(x + 4)^2 + (y + 14)^2 = 2^2

So, for P:

Center = (1,-6)

r = 3

For Q:

Center = (-4,-14)

r = 2

The distance between them is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

Where:

Center = (1,-6) --- (x_1,y_1)

Center = (-4,-14) --- (x_2,y_2)

So:

d = \sqrt{(1 - -4)^2 + (-6 - -14)^2

d = \sqrt{(5)^2 + (8)^2

d = \sqrt{25 + 64

d = \sqrt{89

d = 9.4

Solving (b): The radius;

In (a), we have:

r = 3 --- circle P

r = 2 --- circle Q

By comparison

2 < 3

<em>Hence, circle Q has a smaller radius</em>

4 0
3 years ago
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