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3 years ago

What types of intermolecular interactions are present in alcohol?

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7 0

<span>Specific gravity is the ratio of the density of a substance to the density of a reference substance; equivalently, it is the ratio of the mass of a substance to the mass of a reference substance for the same given volume.</span>

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3Pb2+(aq) + 2Cr(s) → 3Pb(s) + 2Cr3+(aq) What is the number of moles of electrons gained by 3.0 moles of lead ions?

Setler [38]

To determine the electrons gained in this redox reaction, we must balance the charges on the side containing the reduced substance and the side with oxidized substance. In this case, the reduced substance is Pb2+ and the oxidized substance is Cr. In each side, 6 electrons are gained or lose to balance the charges. The answer is 6 electrons.

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3 years ago

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Worksheet Ch.3: % Composition, Molarity, and Other Units for

Ann [662]

The percentage composition by mass of the elements in the compound are:

Ai. The percentage composition by mass of Na in 3.65 g of NaF is 54.8%

Aii. The percentage composition by mass of F in 3.65 g of NaF is 45.2%

Bi. The percentage composition by mass of Zinc in the compound is 67.1%

Bii. The percentage composition by mass of Sulfur in the compound is 32.9%

Percentage composition by mass of an element in a compound can be obtained by using the following formula: $Percentage = \frac{mass of Element}{mass of compound} * 100$

Ai. Determination of the percentage of Na in 3.65 g of NaF

Mass of Na = 2 g

Mass of NaF = 3.65 g

<h3>Percentage of Na =? </h3>

$Percentage = \frac{mass of element }{mass of compound} * 100\\\\Percentage of Na = \frac{2}{3.65} * 100$

<h3>Percentage of Na = 54.8%</h3>

Aii. Determination of the percentage of F in 3.65 g of NaF

Mass of F = 1.65 g

Mass of NaF = 3.65 g

<h3>Percentage of F =? </h3>

$Percentage = \frac{mass of element }{mass of compound } * 100\\\\Percentage of F = \frac{1.65}{3.65} * 100\\\\$

<h3>Percentage of F = 45.2%</h3>

Bi. Determination of the percentage composition of Zn in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

<h3>Percentage of Zn =? </h3>

$Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of Zn = \frac{32.69}{48.72} *100\\\\$

<h3>Percentage of Zn = 67.1%</h3>

Bii. Determination of the percentage composition of Sulphur in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

Mass of S = 48.72 – 32.69 g

Mass of S = 16.03 g

<h3>Percentage of S =? </h3>

$Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of S = \frac{16.03}{48.72} * 100\\\\$

<h3>Percentage of S = 32.9%</h3>

Learn more: brainly.com/question/1350382

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3 years ago

What is one fact you learned about the gases in our atmosphere that you did not know ? PLEASE HELP ! NEED DONE

Mandarinka [93]

Well that is up to you what did you not know but learned recently.

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3 years ago

The process of asking questions is known as

Luda [366]

Inquiring, which comes from the word inquiry which means, "an act of asking a question". In science, the first part of the scientific method is asking questions about the world around you and then after that, conducting experiments to get answers.

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4 years ago

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Please help me solve? Chemistry

oee [108]

1000mL
1mL
100cm
1m
2,290,000 L

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3 years ago