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nignag [31]
3 years ago
13

In which part of the cell is the majority of the energy released from the breakdown of glucose

Chemistry
2 answers:
Vladimir [108]3 years ago
7 0

<em>Answer</em><em>:</em>

<em>Glycolysis</em>

<em>E</em><em>xplanation</em><em> </em><em>:</em>

Glycolysis is the first step in the breakdown of glucose to extract energy for cell metabolism.Many living organisms carry out glycolysis as part of their metabolism. Glycolysis takes place in the cytoplasm of most prokaryotic and all eukaryotic cells.

yan [13]3 years ago
5 0

Answer:

Glycolysis is the first step in the breakdown of glucose to extract energy for cell metabolism. Many living organisms carry out glycolysis as part of their metabolism. Glycolysis takes place in the cytoplasm of most prokaryotic and all eukaryotic cells.

Oxygen is involved in the initial breakdown of glucose to pyruvic acid. Cellular respiration accomplishes two major processes: (1) it breaks glucose down into smaller molecules, and (2) it harvests the chemical energy released and stores it in ATP molecules.

Please give brainliest

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2. Solid sodium reacts with gaseous chlorine to produce sodium chloride.
stich3 [128]
2Na (s) + Cl2 (g) = 2NaCl (s)
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3 years ago
Identify the composition of caffeine. C8H10N4O2 *<br> C=?, H=?, N=?, O=?
Maru [420]
You should know this I am learning it this year and I am in 8th grade) Hydrogen<span>,</span><span>Carbon ,<span>Nitrogen and </span><span>Oxygen

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8 0
3 years ago
Mg + 2HCl → MgCl2 + H2
deff fn [24]

Answer:

Explanation:

This is a limiting reactant problem.

Mg(s)

+

2HCl(aq)

→

MgCl

2

(

aq

)

+ H

2

(

g

)

Determine Moles of Magnesium

Divide the given mass of magnesium by its molar mass (atomic weight on periodic table in g/mol).

4.86

g Mg

×

1

mol Mg

24.3050

g Mg

=

0.200 mol Mg

Determine Moles of 2M Hydrochloric Acid

Convert

100 cm

3

to

100 mL

and then to

0.1 L

.

1 dm

3

=

1 L

Convert

2.00 mol/dm

3

to

2.00 mol/L

Multiply

0.1

L

times

2.00 mol/L

.

100

cm

3

×

1

mL

1

cm

3

×

1

L

1000

mL

=

0.1 L HCl

2.00 mol/dm

3

=

2.00 mol/L

0.1

L

×

2.00

mol

1

L

=

0.200 mol HCl

Multiply the moles of each reactant times the appropriate mole ratio from the balanced equation. Then multiply times the molar mass of hydrogen gas,

2.01588 g/mol

0.200

mol Mg

×

1

mol H

2

1

mol Mg

×

2.01588

g H

2

1

mol H

2

=

0.403 g H

2

0.200

mol HCl

×

1

mol H

2

2

mol HCl

×

2.01588

g H

2

1

mol H

2

=

0.202 g H

2

The limiting reactant is

HCl

, which will produce

0.202 g H

2

under the stated conditions.

pls mark as brainliest ans

7 0
3 years ago
Read 2 more answers
BRAINLIEST PLEASE HELP!!
omeli [17]

Answer:gimme iT OR mama will cOMEEEEEEEEEEEEEEEEE have a nice day

Explanation:

6 0
3 years ago
A 642 mL sample of oxygen gas at 23.5°C and 795 mm Hg, is heated to 31.7°C and the volume of the gas expands to 957 mL. What is
Ratling [72]
We can use the combined gas law equation to find the new pressure of the gas. 
\frac{P1V1}{T1} =  \frac{P2V2}{T2}
where P - pressure 
V - volume
T - temperature 
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
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T1 - 23.5 °C + 273 = 296.5 K
T2 - 31.7 °C + 273 = 304.7 K
substituting the values in the equation 
\frac{1.033 atm *642 mL}{296.5K}=   \frac{P*957mL}{304.7K}
P = 0.712 atm 
the answer closest to this value is A) 0.723 atm
therefore answer is 
<span>A) 0.723 atm</span>
8 0
4 years ago
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