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3 years ago

Find all the complex square roots of w= 36(cos60°+ isin60°). Write the roots in polar form with θ in degrees.

Mathematics

1 answer:

DochEvi [55]3 years ago

4 0

Answer:

3√3+i3

Step-by-step explanation:

w= 36(cos60°+ isin60°)

√w = $w^{1/2}$ =√36(cos60°+ isin60°)

=6√(cos60°+ isin60°)

now using DeMoivre's theorem

=(cos60°+ isin60°)^{1/2}

=(cos60°/2+ isin60°/2)=(cos30°+ isin30°)

w^{1/2}=6(cos30°+ isin30°)

=6(sqrt3/2+i1/2) $\sqrt{frac{3}{2} }$

=3√3+i3

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