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3 years ago

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Find the diameter of a semicircle with an area of 76.97 square yards

2 answers:

Ipatiy [6.2K]3 years ago

6 0

Circle Area = PI*r^2
Semi Circle Area = (PI*r^2)/2
76.97 = (PI*r^2)/2
76.97 * 2 / PI = radius^2
radius^2 = 76.97 * 2 / PI
radius^2 = 153.94 / PI
radius^2 = 49
radius = 7
Diameter = 14 yards

Neporo4naja [7]3 years ago

3 0

Answer:

14 yards

Step-by-step explanation:

The area of a semi circle is given by:

$A = \frac{1}{2} \pi r^2$

where, r is the radius of the semi-circle.

It is given that:

A = 76.97 sq. yards

$\Rightarrow \frac{1}{2} \pi r^2=76.97 \\ \Rightarrow r = \sqrt{\frac{2\times 76.97}{\pi}} = 7 \text { yards}$

We know that diameter is twice of radius.

Thus, diameter of the semicircle is, d = 2 × 7 = 14 yards.

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The slope of all parallel lines are equal.

The slope of a line in the form $y=mx+c$ is m.

1. The given equation is: $y=4x+2$ . The slope of this line is $m=4$ . The slope of the line parallel to this line is also 4.

2. The given equation is $y=\frac{2}{7}x+1$ . The slope of this line is $m=\frac{2}{7}$ .

The slope of the line parallel to it is also $\frac{2}{7}$ .

3. The next equation is $y+9x=13$ . The slope intercept form is $y=-9x+13$ .

The slope of this is $m=-13$ . The line parallel to it also has slope which is -13.

4. The given equation is $y=-\frac{1}{2}x+4$ . The slope of this line and the line parallel to it is $m=-\frac{1}{2}$

5. The equation is 6x+2y=4. We simplify to get: 3x+y=2.

The slope-intercept form is $y=-3x+2$ . The line parallel to this line has slope $m=-3$

6. Assuming the line is $y=-3x+9$ , then the slope is $m=-3$

7. Assuming the line is $-5x+5y=4$ , then the slope-intercept form is $y=x+\frac{4}{5}$ and the slope of the line parallel to this line is m=1

8. The equation is 9x-5y=4. The slope intercept form is $y=\frac{5}{9}x-\frac{4}{9}$ . The slope of the line parallel to this line is $m=\frac{5}{9}$

9. The given equation is $-x+3y=6$ . The slope intercept form is $y=\frac{1}{3}x+2$ . The line parallel to this line also has slope $m=\frac{1}{3}$ .

10. Assuming the given line is 6x-7y=10, then $y=\frac{6}{7}x-\frac{10}{7}$ and the line parallel to it has slope $m=\frac{6}{7}$

11. Assuming the line is $y-x=-3$ , then $y=x-3$ and the slope of the line parallel to it is $m=1$

12. The given line is 3x-5y=6. This implies that $y=\frac{3}{5}x-\frac{6}{5}$

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3 years ago