Question

What is an equation of the line that passes through the point (6,0) and is perpendicular to the line 3x+4y=20

Answer 1

Answer:

The equation of the line is y = 4/3x - 8

Step-by-step explanation:

In order to find this, we first have to find the slope of the original line. We do this by solving for y.

3x + 4y = 20

4y = -3x + 20

y = -3/4x + 5

Now that we have the slope of -3/4 we can find the perpendicular slope. The perpendicular slope of any time is the opposite and reciprocal slope. So we flip -3/4 to get -4/3 and then we make it positive (4/3). Now that we have our new slope, we can input it along with the point into point-slope form to find the equation.

y - y1 = m(x - x1)

y - 0 = 4/3(x - 6)

y = 4/3x - 8