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3 years ago

What is the word form and the expanded form of 427.968?

1 answer:

5 0

The word form for this number is "Four hundred twenty-seven and nine hundred sixty-eight thousandths", and the expanded form of this number is:
400 + 20 + 7 + .900 + .060 + .008

I hope this helps!

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I need the expression

V125BC [204]

Answer:

-7( 8n - m )

- 7 × 8n + 7× m

-56n + 7m

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2 years ago

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The people of Bridgetown wanted to build a bridge across a nearby river. Since they were poor swimmers, their master Trigonomos

VikaD [51]

Answer:

60.2 m

Step-by-step explanation:

Let x represent the width of the river. The distance from the point across from the tree to the second point is 15 m. The angle from this point to the tree across the river is 76°.

This makes the side opposite the angle x, the width of the river. It also means the 15 m side is adjacent to this angle.

The ratio opposite/adjacent is the ratio for tangent; this gives us the equation

x/15 = tan(76)

Multiply both sides by 15:

15(x/15) = 15(tan(76))

x = 15(tan(76)) ≈ 60.2

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3 years ago

adams car can travel 450 miles on a full tank of gas. his gas tank can hold 15 gallons. kennys car can travel 416 miles on a ful

Elden [556K]

450/15 = 30 mpg -- Adam's
416/13 = 32 mpg -- Kenny's

Kenny is going to get the better gas mileage at 32 mpg (miles per gallon)

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3 years ago

Item 10

Rina8888 [55]

How much are the soccer cleats

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2 years ago

10# A consumer advocacy group is doing a large study on car rental practices. Among other things, the consumer group would like

ella [17]

ANSWER:

104

STEP-BY-STEP EXPLANATION:

Given:

Standard deviation (σ) = 700

Confidence level = 95%

Mean error (Eμ) = 135

We have for a confidence level of 95%:

$\begin{gathered} \alpha=100\%-95\%=5\%=0.05 \\ \\ \alpha\text{/2}=\frac{0.05}{2}=0.025 \\ \\ \text{ The corresponding Z value for \alpha/2 = 0.025 is as follows:} \\ \\ Z_{\alpha\text{/2}}=1.96 \end{gathered}$

Now, we calculate the minimum value of the sample size as follows:

$\begin{gathered} n=\left(\frac{Z_{\alpha\text{/2}}\cdot\sigma}{E}\right)^2 \\ \\ \text{ We replacing:} \\ \\ \:n=\left(\frac{1.96\cdot 700}{135}\right)^2 \\ \\ \:n=103.2858\cong104 \end{gathered}$

The minimum sample size needed is 104

3 0

1 year ago