see the attached figure with the letters
1) find m(x) in the interval A,BA (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100
2) find m(x) in the interval B,CB(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20
3)
find n(x) in the interval A,BA (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x
4) find n(x) in the interval B,CB(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30
5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44
6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72
for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72
<span> h'(x) = 1.44 ------------ > not exist</span>
Hmm question is a little confusing but fractions can be represented as division or a part of somthing, like 4 pieces of an 8 slice pizza, or you have 8 peices of pizza and you divide them by 4. Im pretty sure a rational number is any number that can be representated as a fraction. an irrational number is something you cant express as a fraction like the square root of a number or pi.

I think this is what you want? When multiplying with exponents, you either add or multiply the exponents.
When you multiply the exponent:
(x²)³ = 
= 9
When you add the exponents:
(x²)(x³) = 
(x²)(x²) = 

Given :
Amount, A = 5760 Rs.
Interest in the amount, I = 1526 Rs.
To Find :
We need to find the % rate of interest.
Solution :
Let, us assume it is simple interest.
So,

Hence, this is the required solution.
ANSWER: The equation of a line in slope-intercept form looks like the following: y = mx + b
where m is the slope of the line and b is the y-intercept.
Given any 2 points (x1, y1) and (x2, y2) on a line, the slope (m) = (y2-y1)/(x2-x1).
So, Whenever the slope (m) is undefined it means that when you try to
calculate the slope given any 2 points on the line you'll end up with a
zero in the denominator, which is undefined. That is, with an undefined
slope you end up with a vertical line, which has the equation "x=some
number".
m = (y2-y1)/(x2-x1) = (y2-y1)/0 = undefined. This implies that x2=x1. So x is the same for any value of y on the line, which is why the equation is "x=some number" and the line is vertical.
So the equation of a line, in slope-intercept form, with an undefined
slope (m=undefined) crossing through the point (-3, 5) is: x= -3 ,
which is a vertical line.
Hope this helps you