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ANTONII [103]
2 years ago
6

What can be represented as fractions, rational numbers, or irrational numbers?

Mathematics
1 answer:
Delvig [45]2 years ago
3 0
Hmm question is a little confusing but fractions can be represented as division or a part of somthing, like 4 pieces of an 8 slice pizza, or you have 8 peices of pizza and you divide them by 4. Im pretty sure a rational number is any number that can be representated as a fraction. an irrational number is something you  cant express as a fraction like the square root of a number or pi.
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20 points SEND HELP SMART PEEPS IF YOU KNOW THE ANSWER PLEASE HELP
4vir4ik [10]

Answer:

19

Step-by-step explanation:

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4 0
3 years ago
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What is thr difference between dividing 16 by 2 and finding the square roots of 16?
kenny6666 [7]
When you divide a number by two, you find the number that if you add it to itself, become the original number. 

When you square root a number, you find the smaller number that becomes the bigger number if you multiply it by itself.

For sixteen, if you divide it by two, you get 8, while if you square root it, it becomes 4.

5 0
3 years ago
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When comparing the results of multiplying polynomials using the horizontal method and the vertical method, ____________. the ver
Anni [7]

Answer:

The result will always be the same

Step-by-step explanation:

3 0
2 years ago
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Which expressions are equivalent to 1 divided m/6? Check all that apply
jenyasd209 [6]

Answer:

option A, option C, option D

Step-by-step explanation:

a) 1 ÷ m/6

can be written as

\frac{1}{1}÷ \frac{m}{6}

b) sides in (m/6) will change if both has to multiply

c) 1 ÷ m/6

can be written as

1 * 6/m

1(\frac{6}{m}) and wont make change to answer. so matches with the question.

d)

1 ÷ m/6

1 * 6/m

1 * 6 * \frac{1}{m}

6 * \frac{1}{m}

6 ÷ m ..therefore true

e)

1 ÷ m/6

1 * 6/m

6/m    ....does not match or can be converted to the following so wrong

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6 0
2 years ago
Question 3, help please!
White raven [17]

The answer is not defined.

Explanation:

The given matrix is $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$

The matrix $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]$ has dimensions 2\times 2

This means that the matrix has 2 rows and 2 columns.

Also, the matrix $\left[\begin{array}{l}{1} \\ {0}\end{array}\right]$ has dimensions 2\times1

This means that the matrix has 2 rows and 1 column.

Since, the matrices can be added only if they have the same dimensions.

In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.

Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.

Hence, the addition of these two matrices is not defined.

4 0
3 years ago
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