Question

The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individually. Yesterday, she bought the same number of water bottles as candy bars to sell at the snack bar. If she bought the lowest number of items possible, how many packs of each item did she buy? 5 packs of bottled water and 5 packs of candy bars 4 packs of bottled water and 7 packs of candy bars 8 packs of bottled water and 14 packs of candy bars 20 packs of bottled water and 35 packs of candy bars

Answer 1

Answer:

8 packs of bottled water and 14 packs of candy bars

Step-by-step explanation:

Provided,

Each pack of water bottles = 35 bottles

Each pack of candy = 20 candy

Since quantity of candy in each pack is small than quantity of water bottle in each pack, in order to have same quantity in numbers of both bottles and candies,

Purchase quantity of candy packs shall be more than the pack of water bottles.

Further, with this option 1 and 2 are not valid as candy packs are same or less than packs of water bottle.

In option 3 and 4, option 3 have smaller quantities as provided manager bought the least possible quantity.

Accordingly

Option 3

8 packs of water bottle = $8 \times 35 = 280 \ water\ bottles$

14 packs of candy = $14 \times 20 = 280 \ candies$

Since the quantities of water bottles and candies are same this is an opt answer.

Answer 2

Answer:

4 packs of bottled water and 7 packs of candy bars

Step-by-step explanation:

35x40=140

20x7=140

None of the other factors equal 140

So, the answer is  4 packs of bottled water and 7 packs of candy bars.