x° = 43°
Solution:
The lines AD, BE and CF are intersecting lines.
Given m∠AGF = 47°, m∠BGC = 90°, m∠DGE = x°.
To find the value of x°:
Line BE and line CF intersect at the vertex G.
∠BGC and ∠FGE are vertical angles.
<u>Vertical angle theorem:</u>
If two angles are vertically opposite then they are congruent.
By vertical angle theorem, ∠BGC ≅ ∠FGE
⇒ m∠FGE = 90°
Sum of the angles in a straight line = 180°
In line AD,
m∠AGF + m∠FGE + m∠DGE = 180°
⇒ 47° + 90° + m∠DGE = 180°
⇒ 137° + m∠DGE = 180°
⇒ m∠DGE = 180° – 137°
⇒ m∠DGE = 43°
⇒ x° = 43°
Hence the value of x° is 43°.
Answer:
1. 1/18
2. 49/144
3. 5/24
4. 1/4
Step-by-step explanation:
FULL DISCLAIMER these may or may not be correct i have only worked with stats and probability a few times
Check the picture below.
recall, the bearing is always starting from the North line clockwise.
Answer:
23m-18
Step-by-step explanation:
2(7m−5)+(−8+9m)
Remove parenthesis
2(7m-5)-8+9m
expand
14m-10
14m-10-8+9
simplify
23m-18
Ask me for more questions brainliest please.
Answer:
The answer is A
Step-by-step explanation: