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3 years ago

Draw the major organic product that is expected when cyclopentanecarboxylic acid is treated with each of the following reagents:

Chemistry

1 answer:

son4ous [18]3 years ago

8 0

Answer:

a. Sodium cyclopentanecarboxylate

b. No reaction

Explanation:

In this case, in the cyclopentanecarboxylic acid we have a carboxylic acid functional group. Therefore we have an "acid". The acids by definition have the ability to produce hydronium ions ( $H^+$ ).

With this in mind, for molecule a. we will have an acid-base reaction, because NaOH is a base. When we put together an acid and a base we will have as products a salt and water. In this case, the products are Sodium cyclopentanecarboxylate (the salt) and water.

For the second molecule, we have the hydronium ion ( $H^+$ ). This ion can not react with an acid. Because, the acid will produce the hydronium ion also, so a reaction between these compounds is not possible.

See figure 1

I hope it helps!

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A sample of nickel is heated to 99.8 degrees C and placed in a coffee cup calorimeter containing 150.0g water at 23.5 degrees C.

vesna_86 [32]

Answer: The mass of nickel that was originally heated is 28.4 grams.

Explanation:

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of nickel = ?

$m_2$ = mass of water = 150.0 g

$T_{final}$ = final temperature = 25.0°C

$T_1$ = initial temperature of nickel = 99.8°C

$T_2$ = initial temperature of water = 23.5°C

$c_1$ = specific heat of nickel = 0.444 J/g°C

$c_2$ = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

$m_1\times 0.444\times (25.0-99.8)=-[150.0\times 4.186\times (25.0-23.5)]$

$m_1=28.4g$

Hence, the mass of nickel that was originally heated is 28.4 grams.

3 0

3 years ago

Read 2 more answers

You titrate 25.00 ml of 0.1894 M acetic acid with 0.2006 M NaOH. How many ml of NaOH (to four significant figures) will be requi

Anvisha [2.4K]

Answer:

23.60 mL NaOH

Explanation:

The reaction is CH3COOH + OH- --> CH3COO+ + H2O

Since the reaction is one-to-one, we can use M1V1 = M2V2.

M1 = 0.1894 M CH3COOH

V1 = 25.00 mL CH3COOH

M2 = 0.2006 M NaOH

V2 = ?

Solve for V2 --> V2 = M1V1/M2

V2 = (0.1894 M)(25.00 mL) / (0.2006 M) = 23.60 mL NaOH

8 0

3 years ago

Match the prefix used in naming binary molecule compounds with its corresponding number

VARVARA [1.3K]

Nona= 9, hepta= 7, hexa= 6, tetra= 4

8 0

3 years ago

In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How

____ [38]

Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

Ca: 40 g/mole
F: 19 g/mole

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

$moles=\frac{0.0016 grams*1 mole}{78 grams}$

moles=2.05*10⁻⁵

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

$mass of CaF_{2}=\frac{1000 mL*1g}{1mL}$