Since the slopes of the two lines are the not equal, they will have only one solution. The solution will be a point and can be found using the method given below.
We can find the solutions by simultaneously solving the two equations.
From first equation, the value of y comes out to be:
Using this value of y in second equation, we get:
Using this value of x, we can find y:
Therefore, there is only one solution to the given equations is which is (12, -9)
Answer:
2330.51 miles
Step-by-step explanation:
Given that the speed of the airplane = 610 mph.
The airplane leaves an airport at 9:00 P.M. with a heading of 270 degrees and at 10:00 P.M., the pilot changes the heading to 310 degrees.
So, for 1 hour the plane is heading at 270 degrees and for 3 hours, from 10:00 p.m to 1:00 a.m, the plane is heading at 310 degrees as shown in the figure.
As, distance = time x speed, so
The distance covered at 270 degrees, 
miles.
The distance covered at 310 degrees, 
miles.
Total distance covered, d, is the magnitude of the sum of vectors 
and 
as shown in the figure.
The angle between the vectors and , 
degree.
Magnitude of sum of the vectors \vec{d_1} and \vec{d_2},
miles
Hence, at 1:00 a.m, the airplane is at a distance of 2330.51 miles from the airport.
The upper quartile for the data set given below is. 14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29
LekaFEV [45]
Ok, first we need to organize.
<span>14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29
</span>3, 8, 9, 11, 12, 14, 17, 22, 23, 27, 29.
First, we need to find the median, the or the middle, which is 14.
Now that we know the median is fourteen, we take away all numbers to the left of 14, including 14: 17, 22, 23, 27, 29. Now just find the median in this new set of numbers. This will give us our upper quartile, which is 23. Hope this helped, and don't forget to drop a like.
Answer:
acute
Step-by-step explanation:
1. It cannot be right angle as the sides does not satisfy pythagoras theorem.
2. It cannot be obtuse angle as it does not satisfy the rule:
- the length of one side of a triangle must be greater than the differnce and less than the sum of the lengths of the other two sides.
4-3 =1 <6 4+3=7>6
