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3 years ago

I need help please

Mathematics

2 answers:

Dima020 [189]3 years ago

6 0

It's either A or D.

erica [24]3 years ago

6 0

Answer:

-r^2+5r+6

Step-by-step explanation:

The parentheses are there to mess you up, ignore them. Combine like terms, 2 r^2 + (-3) r^2

r + 4r

-1 + (-5)

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Given; D is the Midpoint of CE / Prove DE =1/2CE

aleksley [76]

Answer:

Check explanation

Step-by-step explanation:

Here, we want to make a prove;

Mathematically , since D is the midpoint of CE

Then;

CE = CD + DE

Also, since D splits the line segment into two equal parts as the midpoint, then CD must be equal to DE

I.e CD = DE

Hence, we can express CE as follows;

CE = DE + DE

CE = 2 DE

Divide both sides by 2

CE/2 = DE

Hence; DE = 1/2 CE

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2 years ago

What is the proportional relationship between 200 and 500?

goldenfox [79]

Answer:

Step-by-step explanation:

300 hundred no explaination

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3 years ago

The histogram shows the distribution of hurricanes that have hit a country from 1851 through 2015, where 1 is the weakest level

aleksandrvk [35]

Answer:

a) mean = 0.2

variance = 0.0391

standard deviation = 0.198

b) The average hurricane is aprox. category 2.* (B)

Step-by-step explanation:

In order to find the mean, variance, and standard deviation, let us for a table for the data:

level x

1 0.411

2 0.278

3 0.221

4 0.080

5 0.010

Calculating the mean ( $\bar{x}$ )

$\bar{x} = \frac{x_1+x_2+x_3+x_4 + x_5}{n}\\\\\bar{x} = \frac{0.411 + 0.278 + 0.221 + 0.080 + 0.010}{5}\\\bar{x} = \frac{1}{5}\\ \bar{x} = 0.2$

∴Mean = 0.2

level x $x- \bar{x}$ $(x - \bar{x})^2$

1 0.411 0.211 0.0445

2 0.278 0.078 0.0608

3 0.221 0.021 0.000441

4 0.080 -0.12 0.0144

5 0.010 -0.19 0.0361

$\sum(x - \bar{x})^2 = 0.1562$

$variance = \frac{\sum(x - \bar{x})^2}{n-1} \\variance = \frac{0.1562}{4} \\variance = 0.0391$

standard deviation = √(variance)

Standard deviation = √(0.0391)

Standard deviation = 0.198

b) the average hurricane is aprox. category 2 (B)

8 0

3 years ago

Which expression is equivalent to √2x^5/18? Assume x > 0.

lord [1]

$\sqrt{\dfrac{2x^5}{18}}=\sqrt{\dfrac{2}{18}\cdot x^2\cdot x^2\cdot x}=\sqrt{\dfrac{1}{9}\cdot x^2\cdot x^2\cdot x}=\sqrt{\dfrac{1}{9}}\cdot\sqrt{x^2}\cdot\sqrt{x^2}\cdot\sqrt{x}=\\\\\\=\dfrac{1}{3}\cdot x\cdot x\cdot\sqrt{x}=\boxed{\dfrac{x^2\sqrt{x}}{3}}$

Answer A.

5 0

3 years ago

Read 2 more answers

Can yall help me? I will give 100 points please don't scam me.

allochka39001 [22]

Answer:

D and B

Step-by-step explanation:

D for the first question and B for the second one

8 0

2 years ago

Read 2 more answers