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tatyana61 [14]
4 years ago
10

What is 43.586 rounded to the nearest tenth

Mathematics
1 answer:
Nonamiya [84]4 years ago
8 0


43.586 rounded to the nearest 10th would be 43.6

You just have to look at the number to the right 43.5<u>8</u>

if the number is 5 or more then you round up, if it's lower then the number remains the same.

Hope this helps you :)<u />

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Scott needs to mail a USB drive to a friend. He uses 41-cent stamps and 8-cent stamps to pay $1.87 in postage. How many of each
Brrunno [24]

Answer:

4 41cent stamps would be $1.64/ 3- 8 cent stamps would be 23 cents/ $1.64 + 23= $1.87

Step-by-step explanation:

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3 years ago
Sarris daily tips this work week were $43, $32, $65, $88, $50 and $72. Is Sarah correct in thinking that the mean accurately rep
ella [17]
The answer is A.

Add all the number values together and then divide it by the number of values you have: 43+32+65+88+50+72=350
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7 0
3 years ago
What is the value of x?
Ksenya-84 [330]

Step-by-step explanation:

\frac{360 - 2(x  +  30)}{2}  = x \\  360 - 2x - 60 = 2x \\ 300 - 4x = 0 \\ 4x = 300 \\ x = 300  \div 4  = 75

4 0
3 years ago
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A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline
dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So P(B) = 0.35

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

So

P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125

Probability

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667

46.67% probability that they flew with airline B.

5 0
3 years ago
Math work please help wioth my math
Juli2301 [7.4K]

Answer:

Figure A is scalene and probably obtuse.

Figure B is scalene and right.

Figure C is equilateral and acute.

Figure D is isosceles and right.

Figure E is isosceles and acute.

I am so sorry if I did a few wrong, I'm in Middle-School so I don't know much. I hope I get everything correct!

7 0
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