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3 years ago

Hello i need help.....

Mathematics

1 answer:

raketka [301]3 years ago

4 0

Ok, so the the answer is 1d + 2g.
Hope this helps :)

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Select the equivalent expression.

ZanzabumX [31]

the equivalent expression is C

3 0

3 years ago

Stuck, anyone can help?

expeople1 [14]

Answer:

Step-by-step explanation:

$\sqrt{x-3}$ = x - 5 ( x ≥ 3 )

( $\sqrt{x-3}$ )² = ( x - 5 )²

x - 3 = x² - 10x + 25

x² - 11x + 28 = 0

(x - 4)(x - 7) = 0

$x_{1}$ = 7

$x_{2}$ = 4

Check the answer:

1). x = 7

$\sqrt{7-3}$ = 7 - 2

√4 = 2

2 = 2

2). x = 4

$\sqrt{4-3}$ = 4 - 5

1 = - 1 (False statement) ⇒ x = 4 is an extraneous solution.

6 0

2 years ago

Find the solution to the system of equations. x+y+z=23 y+z=14 z=9

Ne4ueva [31]

A) x+y+z=23
B) y+z=14
C) z=9
Since z = 9 then
A) x + y = 14
B) y = 5
A) x + y+ z=23
A) x + 5 + 9 = 23
A) x = 9

3 0

2 years ago

If angle JKM= 15x-48 and angle L= 5x+12 and angle M= 40, find angle MKL

horrorfan [7]

JKM = M + L
15x - 48 = 40 + 5x + 12
10x - 48 = 52
10x = 100
x = 10
JKM = 15(10) - 48 = 102

180 = JKM + MKL
180 = 102 + MKL
MKL = 180 - 102 = 78

5 0

3 years ago

If ln(4x+y)=2x-3,then dy/dx=

Viktor [21]

$\ln(4x+y)=2x-3$

Differentiate both sides wrt $x$ :

$\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}$

By the chain rule, we get

$\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2$

$\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2$

Solve for $\frac{\mathrm dy}{\mathrm dx}$ :

$4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y$

$\boxed{\dfrac{\mathrm dy}{\mathrm dx}=8x+2y-4}$

4 0

2 years ago

Hello i need help.....​

Hello i need help.....