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Yakvenalex [24]
3 years ago
11

(3x^2+4x-2)-(4x^2-2x-5)

Mathematics
2 answers:
garik1379 [7]3 years ago
8 0
12x^4-8x+10


.............................
















stiv31 [10]3 years ago
4 0
-x^2+6x+3
hope this helps :)
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Rectangle ABCD is the image of ABCD after the reflection of which of the following lines
HACTEHA [7]

Answer My best guess is D

Step-by-step explanation:

7 0
3 years ago
Comparing Relationships with Tables1. Decide whether each table could represent a proportional relationship.If the relationship
yan [13]

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y=kx

where

k is the constant of proportionality

Verify each table

table a

Let

x ----> distance

y ----> sound level

For each ordered pair calculate the value of k

k=y/x

so

(5,85) -----> k=85/5=17

(10,79) ----> k=79/10=7.9

the values of k are differents

that means

the table nor represent a proportional relationship

table b

let

x ----> volume

y ----> cost

k=y/x

(16,1.49) ----> k=1.49/16=0.093125

(20,1.59) ----> k=1.59/20=0.0795

the values of k are differents

that means

the table nor represent a proportional relationship

6 0
2 years ago
If y=26−(3x+2), then x = ?
Anna71 [15]

Answer:

-1/3y +8 = x

Step-by-step explanation:

y=26−(3x+2)

Distribute

y = 26 -3x-2

Combine like terms

y = 24 -3x

Subtract 24 from each side

y -24 = -3x

Divide each side by -3

y / -3 -24/-3 = -3x/-3

-1/3y +8 = x

3 0
3 years ago
Suppose f left parenthesis x right parenthesis right arrow 150f(x)→150 and g left parenthesis x right parenthesis right arrow 0g
BigorU [14]

Answer:

\lim_{x \to 3} (\frac{f(x)}{g(x)} )=- \infty

Step-by-step explanation:

Given that:

f(x) approaches 150, and

g(x) approaches 0, with g(x) < 0,

as x approaches 3.

This means:

\lim_{x \to 3} f(x)=150 \\\\ \lim_{x \to 3} g(x)=0

We need to evaluate:

\lim_{x \to 3} (\frac{f(x)}{g(x)} )

Distributing the limit to numerator and denominator, we get:

\frac{ \lim_{x \to 0} f(x) }{ \lim_{x \to 0} g(x)}\\\\ = \frac{150}{0}

The expression will result in infinity as the answer, but since, g(x) < 0, this means g(x) is approaching 0 from the negative side. As a result, the expression 150/0 will approach negative infinity as x will approach 3.

Therefore, we can conclude:

\lim_{x \to 3} (\frac{f(x)}{g(x)} )=- \infty

3 0
3 years ago
What is the value of 3/5 ÷ (-2/9)? <br><br><br><br> 69 points for good luck!!!!
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Answer:

-2.7

Step-by-step explanation:

8 0
3 years ago
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