- They lose 33% of games i.e 0.33
- They win 67% of games i e 0.67
So
- P(A)=0.33
- P(A')=0.67
Now
- They win from 15games=10
- They lose=5
The required probability
So probability
- 0.213(100)=21.3%
Option B
If the distance from C to C' is 8 and the scale factor is 5. What is the distance from A to C?
1 answer:
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l=51
m=78
n=51
n and l have the same value since it’s an isosceles triangle, so that’s why I doubled 4x-9
