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3 years ago

What is the length of the missing leg 15 and 9 meters

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

4 0

Answer: 12

Step-by-step explanation: I assume you are talking about a triangle in which the Hypotenuse is 15 and leg A is 9

in this case we have to use a reverse pythagorean theorem

the original one is a^ + b^ = c^ then reverse it to get c^ - a ^ = b^

we know that C is 15 and A is 9 so substitute

15^ - 9^ = b^

15 ^ = 225 and 9^ = 81 so substitute again

225 - 81 = b^ then subtract

144 = b^ you know that the square root of 144 is 12 because 12 x 12 = 144

so 12 is the last side

hope this helps mark me brainliest if it did

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3 years ago

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VladimirAG [237]

The value of the given equation is –0.37458.

Solution:

Given equation is:

$$\frac{\tan 1.1-\tan 4.6}{1+\tan 1.1 \tan 4.6}$

Let us first find the values.

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Substitute these values in the given equation.

$$\frac{\tan 1.1-\tan 4.6}{1+\tan 1.1 \tan 4.6}$

$$=\frac{1.96475-8.86017}{1+1.96475 \times 8.86017}$

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Answer:

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