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Talja [164]
3 years ago
12

How will using ascending order on a field that contains dates sort a list?

Computers and Technology
2 answers:
attashe74 [19]3 years ago
5 0

Your answer is from oldest to newest so I would assume B.

4vir4ik [10]3 years ago
4 0

Answer:

from the earliest to the latest date in chronological order

Explanation:

Ascending order means going from the smallest to the largest in a list. When we are talking about dates, it means to organize from the oldest date to the most recent date. So, according to this, if you are using ascending order on a field that contains dates you will sort the list from the earliest to the latest date in chronological order.

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Answer:A flowchart is a diagram that depicts the steps involved in solving a problem. The following flowchart shows how to output the multiplication table ( n * 1 to m * 1) of a number, n and m:

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Which of the following translates packets so that the node can understand them once they enter through a port?
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Which are examples of copyrighted online materials? Check all that apply.
Stella [2.4K]
The answers are 1, 3, and 5.
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Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For f
julia-pushkina [17]

Complete Question:

Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?

Answer:

a) 51.2 msec.  b) 5.12 msec

Explanation:

If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:

  • Tw = K*512* bit time

The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:

a) BW  = 1 Mbps = 10⁶ bps

⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec

b) BW = 10 Mbps = 10⁷ bps

⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec

5 0
3 years ago
Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)
White raven [17]

Answer:

Following are the code to the given question:

#include<iostream>//defining header file

using namespace std;

int main()//defining main method

{

float clspat,test,asst,exam,practice,total,average;//defining floating variable

char name[100];//defining char variable to input value

cout<<"Enter Name of Student: ";//print message

cin>>name; //input value

cout<<"Enter scores in following scoring items between 0 and 100:"<<"\n";//print message

cout<<"Enter class participation score: ";//print message

cin>>clspat;//input value

cout<<"Enter test score: ";//print message

cin>>test;//input value

cout<<"Enter assignment score: ";//print message

cin>>asst;//input value

cout<<"Enter exam score: ";//print message

cin>>exam;//input value

cout<<"Enter practice score: ";//print message

cin>>practice;//input value

total=clspat+test+asst+exam+practice;//calculating total value

average=total/5;//calculating average value

cout<<endl<<"SCORE CARD OF "<<name<<"\n"<<"-----------------------"<<"\n";//print value with message

cout<<"Total score: "<<total<<"\n";//print message with value

cout<<"Average score: "<<average; //print message with value

}

Output:

please find the attached file.

Explanation:

In this code, the floating-point variable is declared, which is used for input value from the user-end and after input the floating-point value it uses the "total, average" variable to calculate its respective values and store its value with init, after storing the value into the variable it uses the print method to print its values.

5 0
3 years ago
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