I am confused as to what your question is specifically asking but the chemical formula for aerobic respiration is:
Oxygen + Glucose --------> Carbon Dioxide + Water
O₂ + C₆H₁₂O₆ --------> CO₂ + H₂O
Hopefully this will aid you in answering your question :)
The answer is <span>Reuptake.
Have a nice day :-)</span>
Answer:
1. P120 is degraded in the 26S proteasome
2. The 26S proteasome has a major role in protein degradation and is critical for protein homeostasis
3. Cell cycle and DNA replication are cellular processes regulated by the Ras and NFkB pathways
Explanation:
The proliferation-associated nucleolar protein (p120) is a protein known to be expressed during the interphase of the cell cycle, specifically in G1 and early S phase, where any problem with DNA replication trigger a checkpoint, i.e., a molecular cascade of signaling events that suspend DNA replication until the problem is resolved. In mammalian cells, the 26S proteasome is responsible for catalyzing protein degradation of about 80% (or even more) of their proteins. The 26S proteasome acts to degrade rapidly misfolded and regulatory proteins involved in the cell cycle, thereby having a major role in protein homeostasis and in the control of cellular processes. It is for that reason that inhibitors that block 26S proteasome function have shown to be useful as therapeutic agents in diseases associated with the failure of protein degradation mechanisms (e.g., multiple myeloma). The NF-κB are highly conserved transcription factors capable of regulating different cellular processes including, among others, cellular growth, inflammatory responses and apoptosis. Moreover, the MAPK/ERK pathway is able to transduce different signals received on the cell surface to the nucleus. The MAPK/ERK pathway is activated when a singling molecule binds to a cell receptor which triggers a signaling cascade that ends when a transcription factor induces the expression of target genes, ultimately producing a response in the cell (for example, the progression through the cell cycle).
Hey!
8= B : adenine with thymine , guanine with cytosine.
9= False : its not single , *dual* helical structure.
10= Every humans' DNA is different but its as similar as our relatives' DNAs as far as i know so its False.
11 = The two backbones of the DNA molecule consists a deoxyribose sugar ^with 5 carbone^ and a phosphate so the correct answer is B
12= Procaryotes' Genomes are simpler- structured than eukaryotes' so procayotes DNA is 1/1000 of eukaryotes.I couldnt translate the options correctly (im not native sorry) but i think its B according to my knowledge of that XD
13= the amount of adenine, guanine, thymime and cytosine must be same so the correct option is %40as well.
Hope it helps!!!
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