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Sedaia [141]
3 years ago
11

4. What is the rule of the nth term of the geometric sequence with

title="a_{4}" alt="a_{4}" align="absmiddle" class="latex-formula"> = -18 and the common ratio r = 2?
a. a_{n}=2.25(2)^{n-1}

b. a_{n}=2(2.25)^{n-1}

c. a_{n}=2(2.25)^{n-1}

d. a_{n}=-2.25(2)^{n-1}

e. a_{n}=-2.25(-2)^{n-1}
Mathematics
1 answer:
hram777 [196]3 years ago
7 0

Answer:

\text{d.}\quad a_n=-2.25(2)^{n-1}

Step-by-step explanation:

The common ratio is given as 2, so the base of any exponential must be 2 (not -2 or 2.25). The 4th term is negative, so the initial value must be negative (since the multiplying factor is positive). The only selection matching these requirements is d.

You know the general term is ...

... an = a1·r^(n-1)

so the 4th term is

... -18 = a1·2^(4-1) = 8·a1

Then the first term is ...

... a1 = -18/8 = -2.25 . . . . . confirms our choice of answer d.

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Please help me gow to this bro , im confused
Airida [17]
Ok so remember that a circle is 360 degrees and a line is 180 degrees
so

IKJ
ok so we see that we have a triangle
to find the internal angles (which add to 180)
we do, opposite angles are equal
JIK=59
also CJI+KJI=180 so 132+KJI=180, KJI=48
so
59+48+IKJ=180
73=IKJ




HIB
we can assume that AB is paralell to CD
so therefor IJK=HIB=48 (from previous question)

EIJ is adding to EIH to get 180
EIJ+59=180
EIJ=121

AIK=AIJ+JIK
JIK=59
AIJ=HIB=48
AIK=59+48=107


IKJ=73
HIB=48
EIJ=121
AIK=107
6 0
3 years ago
The perimeter of a rectangular garden is 292 feet. If the width of the garden is 67 feet, what is its length?
olga2289 [7]
79 is the length because
292-2(67)= 158
158/2 = 79
7 0
3 years ago
Read 2 more answers
Points A and B are on the different sides of a line 1, the distance between point A and the line lis 10 in, the distance between
givi [52]

Answer: Distance between O and the line 1 is 3 inches.

Explanation:

Since we have given that

Distance between point A and the line 1 = 10 inches

Distance between point B and the line 1 = 4 inches

Total length of segment AB is given by

10+4=14\ inches

Since O is midpoint of the line segment AB.

so, AO is given by

\frac{14}{2}=7\ in.

Now, Distance between O and the line 1 is given by

10-7=3\ in.

Hence, Distance between O and the line 1 is 3 inches.

7 0
3 years ago
The height of 6 pictures placed end to end on a bulletin board is 57 centimeters.
Elden [556K]
Ummm I think b orrr A good luck!
7 0
2 years ago
Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati
Brrunno [24]
Remember that <span>an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.
 
Lets solve our equation to find out what is the extraneous solution:
</span>\sqrt{x-3} =x-5
(\sqrt{x-3})^2 =(x-5)^2
x-3=x^2-10x+25
x^2-11x+28=0
(x-4)(x-7)=0
x-4=0 and x-7=0
x=4 and x=7
<span>
So, the solutions of our equation are </span>x=4 and x=7. Lets replace each solution in our original equation to check if they are valid solutions:
- For x=7
\sqrt{x-3} =x-5
\sqrt{7-3} =7-5
\sqrt{4} =2
2=2
We can conclude that 7 is a valid solution of the equation.

- For x=4
\sqrt{x-3} =x-5
\sqrt{4-3} =4-5
\sqrt{1} =1
1 \neq 1
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: <span>D. the extraneous solution is x = 4</span>
7 0
3 years ago
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