This is considered as decision making under risk.
Decision Making Under Risk
A circumstance in which the implications of the chosen course of action and the likelihood that it will occur are understood is referred to as decision-making under risk . For instance, the lottery selection tasks are frequently employed to examine the nature of decision-making in risky situations.
We make the assumption that there are two or more choices and that each alternative's characteristics are explicitly specified. For each attribute, the CV (coefficient of variation) is configured in case of such decision under risks. And, since in the given question, decision maker is supposed to consider several possible outcomes for each alternative, each with a given probability of occurrence. Thus the decision made will be decision under risk.
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Answer:
x=2
Step-by-step explanation:
x=2
x+1=3
and 3 is a prime
Answer:
y = 2.54x + 62.38
Step-by-step explanation:
Let x represent the duration or stipulated years after the year 2006
Let y represent the amount of ticket that is sold
Let m represent the average increase in the price every year
y = mx + c
y = 2.54 × x + 62.38
y = 2.54x + 62.38
9514 1404 393
Answer:
it is application of the multiplication property of equality
Step-by-step explanation:
You can use "cross products" to solve any proportion. What looks like a "cross product" is just application of the multiplication property of equality. That property says the variable value is unchanged if both sides of the equation are multiplied by the same value.
For your fraction, the "cross product" is what you get when you multiply both sides of the equation by 500.

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Note that the next step here is to divide by the x-coefficient, the 5 that was in the left-side denominator.

Please also note that this is exactly the same result you would get by multiplying the original equation by the original denominator of x.
(a) The integral is equal to the area of the triangle; it has height 20 and base 10, so the area is 20*10/2 = 100.
(b) The integral is equal to the area of the semicircle with radius 10. It's also under the horizontal axis, so the area is negative. The semicircle has area
, so the integral is -50π.
(c) First compute

which is the area of the triangle on the right. It has height and base 5, so its area is 25/2.
Then split up the desired integral as

and plug in the integral values you know:
