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3 years ago

This is a graph of which function?

Mathematics

1 answer:

kondaur [170]3 years ago

5 0

The answer is D. Uts D b\c the bottom line is 5 but it's a negative. Then you see how much far is the sides dividing by two.

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The 7th graders at Sunview Middle School were helping to renovate a playground for the kindergartners at a nearby elementary sch

VARVARA [1.3K]

Answer:

90 bags of sand

Step-by-step explanation:

9 feet × 1.5 = 13.5

12 feet × 1.5 = 18

Large pit area= 13.5 × 18 = 243ft squared

The small pit area=9 × 12 = 108ft squared

243 / 108 = 2.25 times larger

This means the large pit needs 2.25 times more sand.

40 × 2.25 = 90 bags of sand

5 0

3 years ago

Read 2 more answers

Yesterday the temperature was 6°C. Today it is -5°C. In degrees Celsius, what is the change in temperature?

Mumz [18]

The temperature went down 11 degrees

5 0

3 years ago

Read 2 more answers

In two games the bobscats scored 109 and 102 point. In two games the Huskies scored 103 and 98 point. By how many points did the

Phoenix [80]

Answer:

10 Pts

Step-by-step explanation:

109 + 102 = 211

103 + 98 = 201

211 - 201 = 10

hOPE THIS HELPs

5 0

4 years ago

PLEASE PLEASE HELP!!

HACTEHA [7]

The answer is 1, 4, and 5 because to be linear, they have to make up a straight line together.

4 0

3 years ago

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. How many ways are there to choose:(

Volgvan

Answer:

The number of ways of selecting of n items form r different items = $^{(n+r-1)}C_{(r-1)}$

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple.

A) How many ways are there to choose 32 candies?

So, n = no. of items = 32

r = no. of types of items = 5

So, No. of ways to choose 32 candies = $^{(32+5-1)}C_{(5-1)}$

= $^{36}C_{4}$

= $\frac{36!}{4!(36-4)!}$

= $58905$

So, No. of ways to choose 32 candies is 58905

B)32 candies with at least a piece of each flavor?

Out of 32 you choose 5 candies of different types

So, Remaining candies = 32 - 5 = 27

So, No. of ways to choose 27 candies = $^{(27+5-1)}C_{(5-1)}$

= $^{31}C_{4}$

= $\frac{31!}{4!(31-4)!}$

= $31465$

So, No. of ways to choose 32 candies with at least a piece of each flavor is 31465

C) 32 candies with at least 4 cherry and at least 6 lemon?

So, you already choose 6+4= 10

So, remaining candies = 32-10 = 22

So, No. of ways to choose 22 candies = $^{(22+5-1)}C_{(5-1)}$

= $^{26}C_{4}$

= $\frac{26!}{4!(26-4)!}$

= $14950$

Hence No. of ways to choose 32 candies with at least 4 cherry and at least 6 lemon is 14950

8 0

4 years ago