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fenix001 [56]
3 years ago
6

In parallelogram ABCD, E is the midpoint of

Mathematics
1 answer:
algol133 years ago
3 0

Answer:

Step-by-step explanation:

Example:

If E, F, G and H are respectively the mid-points of the sides of a parallelogram ABCD shows that ar ( EFGH) = 1/2 ar ( ABCD)

If E, F, G and H are respectively the mid-points of the sides of a parallelogram ABCD show that ar (EFGH) = 1/2 ar (ABCD)

Given: A parallelogram ABCD where E, F, G, H are the mid-points of AB,BC,CD & AD respectively

To prove: ar (EFGH) = 1/2 ar (ABCD)

Proof: Join H & F

Now,

So, AD || BC                  ( Opposite sides of parallelogram are parallel)

> DH || CF                     ( Parts of parallel lines are parallel)

Also, AD = BC               ( Opposite sides of parallelogram are equal)

1/2AD = 1/2 BC

DH = CF

( H is mid-point of AD

 F is mid-point of BC)

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