Find the percent of change when 40 is increased to 83. If necessary, round your answer to the nearest tenth.
2 answers:
You might be interested in
The correct question in the attached figure
we know that
the length of Q is 25% more than the length of p
so
length Q=1.25*40--------> 50 cm
the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18
the answer is
the ratio x:y is 25:18
we know that
the length of Q is 25% more than the length of p
so
length Q=1.25*40--------> 50 cm
the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18
the answer is
the ratio x:y is 25:18
You could set up a ratio:
which then becomes:
which then becomes: