Solve the inequality 2r^2-13x+15<0
2 answers:
Answer:
<u>Step-by-step explanation:</u>
First, factor the inequality and solve for x to find the zeros.
Then, choose test points on the outside of those values and between them.
Plug them in to determine which one(s) yield a negative (< 0).
2x² - 13x + 15 < 0
(2x - 3)(x - 5) < 0
2x - 3 = 0 and x - 5 = 0
x = 3/2 and x = 5
I choose the left test point of 0 (2(0) - 3) × (0 - 5) > 0 (+)
I choose the between test point of 2 (2(2) - 3) × (2 - 5) < 0 (-)
I choose the right test point of 6 (2(6) - 3) × (6 - 5) > 0 (+)
<u />
<u>Illustration of Graph:</u>
+ --- +
←----|----------o----------------|---------------o--------------|----→
0 3/2 2 5 6
Since the "between" test point is the only one that yielded a negative, then the solution is the values between 3/2 and 5.
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Answer:
C. a reflection in the y-axis
Step-by-step explanation:
The mapping statement for the transformation of the vertices of the triangle ABC is given as following:
A(0,2)→A'(0,2)
B(2,9)→B'(-2,9)
C(4,2)→C'(-4,2)
To find the correct transformation for the given statement.
Solution:
From the given statements, the general transformation statement for the the vertices of the triangle can be given as:
The above transformation shows a reflection in the y-axis as the transformation in y-axis changes the sign of the x-coordinate of the point.