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RideAnS [48]
3 years ago
7

Which statements are true regarding the area of circles and sectors? Check all that apply.

Mathematics
2 answers:
krek1111 [17]3 years ago
6 0

Answer:

a,b,d,e

Step-by-step explanation

answer on edg. was right

AveGali [126]3 years ago
3 0

Answer:

The correct options are a,b.

Step-by-step explanation:

The area of sector of a circle equals

Area of a sector = \theta r^{2}

where

\theta is the angle subtended at the center by the sector

r is the radius of circle

This indicates that area of the sector depends on:

1) Radius of circle

2) Angle  subtended at the center by the sector

3) Area of sector does not depend on pi.

Also if we know the area of the sector only  we cannot calculate area of area of whole triangle as we need one more information either angle of the sector and vice versa.

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X + x(x + y) + y; use x = 4, and y = 1
leva [86]

\huge\text{Hey there!}

\huge\text{x + x(x + y) + y}

\huge\text{= 4 + 4(4 + 1) + 1}

\huge\text{= 4 + 4(5) + 1}

\huge\text{= 4 + 20 + 1}

\huge\text{= 24 + 1}

\huge\text{= 25}

\huge\boxed{\textsf{Therefore, your answer is: 25}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

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5 0
2 years ago
Read 2 more answers
(-5/8)×(2/3) what's this answer ?
shutvik [7]

Answer:

Q = -5/8 * 2/3

Multiply both numbers like your multiplying actual numbers.

<em><u>(-5 * 2)/(8*3)</u></em>

<h2><em><u></u></em></h2><h2><em><u>A = -10/24 = -5/12</u></em></h2><h2><em><u>Hope this helps</u></em></h2>
6 0
2 years ago
3 letters without replacement 4 letters A B C D how many ways can this be done if the order of the choices matters
Veseljchak [2.6K]

Answer:

Since the order of choice matters, we will permute the values.                       a bit more explanation for this:

If the order of choice did NOT matter, ABC and BCA will be counted as one since order of choice does NOT matter

Since order of choice does matter, ABC , BCA and CAB are all different possibilities for the arrangement of the same 3 letters

Since we have 3 slots:

___  ___ ___

Now, for the first slot. You can out either one if the 4 alphabets in the first slot since no slot has been used as of now

So:

_<u>4</u>_ ___ ___

**Keep in mind that the 4 is the possible number of values this slot can have**

Now that one slot has been used, one of the 4 alphabets has been used and since we are not allowed to repeat the same alphabets, we are left with  3 more alphabets

we can put any one of the 3 alphabets in this second slot, Hence:

_<u>4</u>_ <u>_3_</u> ___

Now that 2 of the 4 alphabets have been used, we are left with only 2 alphabets, so there are only 2 possible alphabets for slot 3

Therefore:

_<u>4</u>_ _<u>3</u>_ _<u>2</u>_

Now that we know the possible alphabets for all 3 slots, we will multiply them with each other to get the total possible number of 3 - alphabet words we can make with 4 alphabets

Total possible words = 4 * 3 * 2

Total possible words = 24

We could've used the formula for Permutation as well

8 0
3 years ago
I’ll give brainliest IF ITS AN ACRUAL ANSWER, ALL USELESS ONES WILL BE REPORTED
Llana [10]

Answer:

C

Step-by-step explanation:

pls mark brainliest

multiply the numerator and denominator by the same number so, that all the fractions have a denominator of 12.

4 0
3 years ago
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Tju [1.3M]
Graph 1: -3 is the slope
Graph 2: 4/5 is the slope
3 0
3 years ago
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