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qaws [65]
3 years ago
13

The project represented by this resource load chart has a maximum limit of 6 units of resource activity in any day. The first ac

tivities that are strong candidates for shifting are:
Business
1 answer:
Charra [1.4K]3 years ago
4 0

Complete Question:

The project represented by this resource load chart (see attached) has a maximum limit of 6 units of resource activity in any day. The first activities that are strong candidates for shifting are:

A) Activity A

B) Activities B and C

C) Activities D and E

D) Activity E and F

Answer:

The first activities that are strong candidates for shifting are:

C) Activities D and E

Explanation:

Activities D and E have a total time of 5 days altogether based on the attached resource load chart.  They have the least time and can be shifted to accommodate other activities before they can be tackled sequentially.

A resource load chart displays the total amount of resources required as a function of time in any given project.  It is the best method for establishing the existence of some resource conflicts across project activities, especially when compared to Gantt Charts, Network Diagrams, and Pareto Diagrams.

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Total Costs (dollars)
Andrei [34K]

The appropriate labels for Curves N and M in the nearby graph is that the Curve N is total cost and Curve M is total variable cost.

<h3>Why is the curve as stated about?</h3>

Because a fixed cost is constant, this is not shown on the graph, however, the movement of the variable cost impacts directly on the total cost as well but it will be higher.

Hence, the appropriate labels for Curves N and M in the nearby graph is that the Curve N is total cost and Curve M is total variable cost.

Therefore, the Option C is correct.

Read more about total cost

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6 0
2 years ago
HELP PLEASE!!! YOU ARE TRYING TO DETERMINE HOW LONG TO STUDY FOR THIS EXAM. EXPLAIN ECONOMICALLY.
Natalija [7]

Answer: What kind of exam is it? Study as long as you can if its flashcards or practice problems.

Explanation:

This is the best way to study

7 0
3 years ago
Productivity is generally more difficult to improve in the service sector than in the manufacturing sector. True False
Dvinal [7]

Answer: True

Explanation:

Productivity is the process of measuring an organization's ability to produce a good or service. While organizations that produce goods can point to the total finished number of products as evidence. It is difficult to improve the service sector's productivity, because of the following;

1. Service industries are labor-intensive

2. Measuring and monitoring service quality are difficult

3. Most service establishments are of small size

4. Using machine technology and labor-saving devices is difficult

4 0
3 years ago
A company purchased a weaving machine for $190,000. The machine has a useful life of 8 years and a residual value of $10,000. It
pav-90 [236]

Answer:

The answer is option (B), accumulated depreciation at end of the second year=36,000+45,600=$81,600

Explanation:

Determine the depreciable cost using the formula below;

depreciable cost=acquisition cost-residual value

where;

acquisition cost=$190,000

residual value=$10,000

replacing;

depreciable cost=190,000-10,000=$180,000

depreciable cost=$180,000

Determine the cost per unit as follows;

depreciable cost=cost per bolt×number of bolts produced

where;

depreciable cost=$180,000

cost per bolt=c

number of bolts produced=75,000 bolts

replacing;

180,000=c×75,000

75,000 c=180,000

c=180,000/75,000=2.4

The cost per bolt=$2.4

annual depreciation for the first year=(2.4×15,000)=$36,000

annual depreciation for the second year=(2.4×19,000)=$45,600

accumulated depreciation at end of the second year=36,000+45,600=$81,600

3 0
3 years ago
Answer each of the following independent questions.
amid [387]

Answer:

Instructions are listed below.

Explanation:

Giving the following information:

Alex Meir recently won a lottery and has the option of receiving one of the following three prizes:

(1) $86,000 cash immediately

(2) $32,000 cash immediately and a six-period annuity of $9,200 beginning one year from today

(3) a six-period annuity of $17,400 beginning one year from today.

1)

A) i= 0.06

i) PV= 86,000

ii) First, we need to calculate the final value of the annuity:

FV= {A*[(1+i)^n-1]}/i

A= annual pay

FV= {9,200*[(1.06^6)-1]}/0.06 + [(9,200*1.06^6)-9,200]= 68,023.31

PV= FV/(1+i)^n= 68,023.31/1.06^6= 47,953.75 + 32,000= $79,953.75

ii) FV= {17,400*[(1.06^6)-1]}/0.06 + [(17,400*1.06^6)-17,400]= 128,652.77

PV= 128,652.77/1.06^6= $90,695.13

B) The option with the higher present value is option 3. Therefore, it is the best option.

2) Weimer will make annual deposits of $170,000 into a special bank account at the end of each of 10 years beginning December 31, 2016.

Assuming that the bank account pays 7% interest compounded annually.

FV= {A*[(1+i)^n-1]}/i

FV= {170,000*[(1.07^10)-1]}/0.07

FV= $2,348,796.15

7 0
3 years ago
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