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solmaris [256]
3 years ago
12

How do I find vertex

Mathematics
1 answer:
algol133 years ago
6 0

Answer:

Get the equation in the form y = ax2 + bx + c.

Calculate -b / 2a. This is the x-coordinate of the vertex.

To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y.

Step-by-step explanation:

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Write the slope-intercept form of the equation of the line; (-5,-4) and prep. To y equals 5x plus 1
ohaa [14]

Answer:

y=-\frac{1}{5} x-5

Step-by-step explanation:

The given line is defined by:  y=5x+1, where we see that the slope is 5 and the y-intercept 1.

In order to find a line perpendicular to the given one, we need it to have a slope that is the "opposite of the reciprocal" of the given slope.

"Opposite" means it would have its sign inverted (in our case from positive to negative); and "reciprocal means that instead of 5, it would be its reciprocal: \frac{1}{5}.

We can write this new line with such slope, and try to find its y-intercept (b) by using the given condition that requires it to go through the point (-5,-4) on he plane:

y=-\frac{1}{5} x+b

we require then that when x=-5, the value of y=-4.

Therefore: -4=-\frac{1}{5} (-5)+b\\-4=\frac{5}{5} +b\\-4=1+b\\b=-4-1=-5

Then our final answer is that the new line should have the form: y=-\frac{1}{5} x-5

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